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8_murik_8 [283]
3 years ago
8

What is the sum of the two lengths having the following measurements? Convert the answer to larger units whenever possible. 

Mathematics
2 answers:
Olegator [25]3 years ago
8 0

The answer is C. 10 yards and 1 foot

Grace [21]3 years ago
3 0

Answer:

C 10yrds 1ft.

Step-by-step explanation:


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beks73 [17]

Answer:

A,C,D

Step-by-step explanation:

5 0
2 years ago
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What is the unit rate for meters per second if a car travels 238 meters in 17 seconds?
madreJ [45]
I assume a unit rate is simply ms^-1 or whatever.

In order to determine m/s one must make the "per whatever" part equal to 1. In this case it is seconds, so we must make seconds equal to 1.

If in 17 seconds it travels 238 metres, that means in 1 second it travels 238/17m=14m

Therefore the unit rate (speed) of the car is 14m/s or 14ms^-1
6 0
3 years ago
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Can somebody help me with this I don’t get it?
Inessa [10]

Answer:

the time means how long it takes to get to that distance below it

Step-by-step explanation:

4 0
2 years ago
* this is pretty difficult for me , provide details if necessary * // ANSWER ASAP //
fredd [130]

Answer:

A.

Step-by-step explanation:

1 radian = 180/π

So

Multiplying both sides by 25π/18

We'll get,

25π/18 (r) = (180/π)×(25π/18)

= (180×25)/18

= 10×25

= 250 degrees

5 0
3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
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