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Finger [1]
2 years ago
14

Selim is ordering concrete spheres to place as barriers in the city park. The spheres cost $2 per square foot, and Selim can spe

nd $20 per sphere. What is the maximum diameter of the spheres he can purchase?
Mathematics
1 answer:
vlada-n [284]2 years ago
4 0

Answer:

1.78 feet.

Step-by-step explanation:

If they cost $20 each and its $2 per square foot, the area of the spheres

is 20 / 2 = 10 ft^2.

Area of sphere = 4 π r^2 = 10   (where r = the radius)

---> r^2 = 10 / 4π

            =   0.796

---> r = 0.892 ft

So the diameter = 2 * r  

                           =  1.78 feet to nearest hundredth.    

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What problem is Chen checking 152x4=608+2=610
tester [92]
The +2 is a reminder to add when he multiply 4*1 (4*1=4+2=6)
4*2=8
4*5=20 (so he writes the 0 with a remainder of 2)
4*1=4+2=6
so,
152x4= 608
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3 years ago
Which expression is equal to zero? 9 + (– 27) ÷ (– 3)
GrogVix [38]

Answer:

-27÷(-3)-9

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Step-by-step explanation:

Hope this helps you.

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3 years ago
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Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i
Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333

So the correct answer is C, the area between the two functions is 4/3 units.

3 0
3 years ago
hi do I have this answer right? I just need someone help me out with this question so I can get the right answer
Kobotan [32]
I belive his answer is wrong B/c the graph does not even start near 310 the first to bars make it to 50 and 150 so even if u add the two together it would only be 200 so, the answer would be B
6 0
3 years ago
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