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Alika [10]
3 years ago
13

hi do I have this answer right? I just need someone help me out with this question so I can get the right answer

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0
I belive his answer is wrong B/c the graph does not even start near 310 the first to bars make it to 50 and 150 so even if u add the two together it would only be 200 so, the answer would be B
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Based only on the given information, it is guaranteed that Ac = bc
qwelly [4]

Answer:

True

Step-by-step explanation:

True because if AC = BC, then the triangles are the same.

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3 years ago
She has found that 5 out of 7 seeds produce corn. She wants to have 10,000 corn bearing plants. How many seeds should see plant
Anton [14]
It would take 70,000 seeds if five out of seven are good. So over a quantity of 50,000 plants desired, you would sow 70,000 seeds.  As 20,000 would statistically fail.
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3 years ago
PARALLEL LINES <br>Find x and y. <br>​
Georgia [21]
4x = (130 - 2x) so x = 65/3

(3y + 40) + (130 -2x) = 180 because the angles are supplementary

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3 0
1 year ago
Read 2 more answers
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
3 years ago
PLSS HELP
Harrizon [31]
Your answer is going to be Letter B
8 0
3 years ago
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