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2 years ago

The distance between two points on a number line can be found by taking the _[blank 1]_ of the _[blank 2]_ of the coordinates.

1 answer:

3 0

The distance between two points on a number line can be found by taking the absolute value of the difference in the coordinates.

Range and Longitude are the units that represent the coordinates in the geographic coordinate system. To make a search, use the call of a place, metropolis, state, or cope with, or click on the vicinity on the map to find lat lengthy coordinates.

A geographic coordinate machine defines -dimensional coordinates based on this planet's surface. It has an angular unit of measure, prime meridian, and datum (which includes the spheroid). As proven in the picture below, traces of longitude have X-coordinates between -a hundred and eighty and +one hundred eighty levels.

The geographic coordinate gadget is a round or ellipsoidal coordinate device for measuring and communicating positions immediately on the earth as range and longitude. It is the only, oldest, and maximum extensively used of the variety of spatial reference structures that are in use, and paperwork is the premise for most others.

Learn more about coordinates here brainly.com/question/11337174

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Evaluate the expression for the given value of the variable. 8p; p=9

kupik [55]

Answer:

Step-by-step explanation:

substitiute the value of p =8(9)

8x9=72

8 0

3 years ago

Read 2 more answers

Wich is equivalent to sqrt10^3/4 x

Sergio039 [100]

Answer:

$( \sqrt[4]{10} ) ^{3x}$

7 0

3 years ago

What’s is the solution to the equation x to the power of 2 =16/25

skelet666 [1.2K]

Answer:

$x=\dfrac{4}{5}$

Step-by-step explanation:

The given equation is :

$x^2=\dfrac{16}{25}$

We need to find the value of x.

When the exponent 2 removes from LHS, it will shift to RHS as square root as follows :

$x=\sqrt{\dfrac{16}{25}}$

We know that, 4×4= 16 and 5×5 = 25

So,

$x=\sqrt{\dfrac{4\times 4}{5\times 5}}\\\\x=\dfrac{4}{5}$

So, the solution of the given equation is 4/5.

4 0

3 years ago

Need this really quick plz

Oduvanchick [21]

Answer:

Let

x=sin-¹u

Sinx=u

let y=tan-¹v

tany=v

Substituting

Sin[x + y]

Applying the sine expansion

Sinxcosy + CosxSiny

Recall x =Sin-¹u

y=tan-¹v

Sin(Sin-¹u)Cos(tan-¹v) +Cos(sin-¹u)Sin(tan-¹v)

Now at this point

Here's what you do

For the first expression

Sin(Sin-¹u)

Let's simplify this

Let P = Sin-¹u

Taking sine of both sides

SinP=u

Draw a Right angled angle for this

Since Sine from SOHCAHTOA is OPP/HYP

Where P is the angle and u is the opposite and 1 is the hypotenuse since u is the same as u/1

substituting Sin-¹u = P

You have

Sin(Sin-¹u) = SinP

and from the triangle you drew

SinP = u

Taking the second express

Cos(tan-¹v)

Let Q=Tan-¹v

taking tan of both sides

tanQ=v

Draw a right angled triangle for this too

Since Tan from SOHCAHTOA is OPP/ADJ

Find the Hypotenuse cos you'll need it

Now Let's do the substitution again

We first said tan-¹v = Q

When we substitute it in Cos(tan-¹v)

We have CosQ

Cos Q from the second right angle triangle you drew is 1/√1+v²

Because CAH is adj/Hyp

the first part of the original Express

Which is

Sin(Sin-¹u)Cos(tan-¹v) is now simplified to

u(1/√1+v²).

Let's Move to the second part of the Original Expression

Cos(Sin-¹u)Sin(tan-¹v)

From our first solution

We said Sin-¹u= P

So replacing it here

we have Cos(sin-¹u) = CosP

let's leave the second one for now which is sin(tan-1v) We'll deal with this after the first

so Cos(Sin-¹u) = CosP

we can still use our first Right angle triangle for this because the angle was P.

so Cos P from that triangle will be

CosP= √1-u²

Now onto the next

Sin(tan-¹v)

From the Second solution of the first we did

we said let Tan-¹v =Q

Substituting this

we have

Sin(tan-¹v) = SinQ

using the second Right angle triangle because its angle is Q

We have

SinQ= v/√1+v²

Answer for second phase Which is

Cos(sin-¹u)Sin(tan-¹v) = √1-u²(v/√1+v²)

We're done

compiling our answers

The answer to

Sin(Sin-¹u - tan-¹v) = u(1/√1+v²) + [(√1-u²)(v/√1+v²)]

You can still choose to factor out 1/√1+v² since it appears on both sides

8 0

3 years ago

Difine complex fraction . give two example of a complex fraction

marin [14]

If in a fraction, the numerator or the denominator or both are fractions, then it is called a complex fraction.

Example 1:

$\frac{\frac{3}{4} }{7}$

Here, since the numerator is a fraction, it is a complex fraction.

Example 2:

$\frac{\frac{1}{2} }{\frac{3}{7} }$

Here, since the numerator and the denominator are fractions, it is a complex fraction.

6 0

3 years ago