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3 years ago

8

A set designer builds a model of the stage and the different pieces of furniture on it. He uses a scale of 5 cm to 1 m. What is

the ratio of a length on the model to a length on the stage?

1 answer:

Akimi4 [234]3 years ago

8 0

5-1

5:1

for every 5 cm there is 1 m

ur welcome ;]

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Seth bought a T-shirt that costs $21.00. If the tax rate was 8%, what was the total cost of the t-shirt?

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Answer:

$22.68

Step-by-step explanation:

21×.08= 1.68

21+1.68=22.68

Total cost =$22.68

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3 years ago

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At 1:00 p.m. u have 24 megabytes of a movie. At 1:15 p.m. u have 96 megabytes. What is the downloads rate in megabytes per minut

guajiro [1.7K]

Answer:

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Step-by-step explanation:

96-24= 72

72/15 minutes= 4.8

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3 years ago

A line passes through the points (1, 4) and (3, –4). Which is the equation of the line?

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3 years ago

Exposure to microbial products, especially endotoxin, may have an impact on vulnerability to allergic diseases. The following ar

Softa [21]

Answer:

A. E ( U ) = 21.5454 , E ( F ) = 8.39333

B. M ( U ) = 17.0 , M ( F ) = 18.0

C. E ( U' ) = 17.0 , E ( F' ) = 7.95384

D. T ( U ) = 9.091% , T ( F ) = 6.667%

Step-by-step explanation:

Solution:-

- Two sample sets ( U ) and ( F ) that define the concentration ( EU/mg ) of endotoxin found in urban and farm homes as follows:

U: 6.0 5.0 11.0 33.0 4.0 5.0 80.0 18.0 35.0 17.0 23.0

F: 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 22.0 9.6 2.0 2.0 0.5

- To determine the mean of a sample E ( U ) or E ( F ) the following formula from descriptive statistics is used:

$E ( X ) = Sum ( X_i ) / n$

Where,

Xi : Data iteration

n: Sample size

Therefore,

$E ( U ) = \frac{Sum (U_i )}{n_u} \\\\E ( U ) = \frac{6.0 + 5.0 + 11.0 + 33.0 + 4.0+ 5.0 +80.0+ 18.0+ 35.0+ 17.0+ 23.0 }{11} \\\\E ( U ) = 21.54545\\\\E ( F ) = \frac{Sum (F_i )}{n_f} \\\\E ( F ) = \frac{2.0 + 15.0 + 12.0 + 8.0 + 8.0 + 7.0 + 6.0 + 19.0+ 3.0+ 9.8+ 22.0+ 9.6+ 2.0+ 2.0+ 0.5 }{15} \\\\E ( F ) = 8.39333$

- To determine the sample median we need to arrange the data for both samples ( U ) and ( F ) in ascending order as follows:

U: 4.0 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0 80.0

F: 0.5 2.0 2.0 2.0 3.0 6.0 7.0 8.0 8.0 9.6 9.8 12.0 15.0 19.0 22.0

- Now find the mid value for both sets:

Median term ( U ) = ( n + 1 ) / 2

= ( 11 + 1 ) / 2 = 12/2 = 6th term

Median ( U ), 6th term = 17.0

Median term ( F ) = ( n + 1 ) / 2

= ( 15 + 1 ) / 2 = 16/2 = 8th term

Median ( F ), 8th term = 8.0

- We will now trim the smallest and largest observation from each set.

- In set ( U ) we see that smallest data corresponds to ( 4.0 ) while the largest data corresponds to ( 80.0 ). We will exclude these two terms and the trimmed set is defined as:

U': 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0

- In set ( F ) we see that the smallest data corresponds to ( 0.5 ) while the largest data corresponds to ( 22.0 ). We will exclude these two terms and the trimmed set is defined as:

F': 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 9.6 2.0 2.0

- We will again use the previous formula to calculate means of trimmed samples ( U' ) and ( F' ) as follows:

$E ( U' ) = \frac{5.0+ 5.0+ 6.0+ 11.0+ 17.0+ 18.0+ 23.0+ 33.0+ 35.0}{9} \\\\E ( U' ) = 17$

$E ( F' ) = \frac{2.0 +2.0+ 2.0 +3.0+ 6.0+ 7.0+ 8.0+ 8.0+ 9.6+ 9.8+ 12.0+ 15.0+ 19.0}{13} \\\\E ( F' ) = 7.95384$

- The trimming percentage is known as the amount of data removed from the original sample from top and bottom of sample size of 11 and 15, respectively.

- We removed the smallest and largest value from each set. Hence, a single value was removed from both top and bottom of each data set. We can express the trimming percentage for each set as follows:

$T ( U ) = \frac{1}{11} * 100 = 9.091\\\\T ( F ) = \frac{1}{15} * 100 = 6.667$ %

- The trimming pecentages for each data set are 9.091% and 6.667% respectively.

7 0

3 years ago

PLS HELP!!! TYSMMMM

Verdich [7]

Answer:

The ar of plot not fenced = 31.59 x 31 = 979.44 sq mts

Step-by-step explanation:

Let the area of the plot which is fenced be 48x and the area of the plot which is not fenced is 31x.

Hence the total area of the plot will be

48x+31x=79x

Here we also given that , total area of plot is 2496 sq mts.

Hence 79x=2496

Dividing both sides by 79 we get ,

x= 31.59

Hence amount of plot fenced = 31.59 x 48 = 1516.55 sq mts.

The amount of plot not fenced = 31.59 x 31 = 979.44 sq mts

8 0

3 years ago