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3 years ago

8

A set designer builds a model of the stage and the different pieces of furniture on it. He uses a scale of 5 cm to 1 m. What is

the ratio of a length on the model to a length on the stage?

1 answer:

Akimi4 [234]3 years ago

8 0

5-1

5:1

for every 5 cm there is 1 m

ur welcome ;]

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One question simple please help

igor_vitrenko [27]

Answer:

$y = \frac{1}{3}x - 9$

Step-by-step explanation:

Standard equation of a line is y = mx + b, where m is the slope.

Given line y = - 3x + 78, slope, m₁ = -3

<em><u>To find the line perpendicular to the given line.</u></em>

The lines are perpendicular to each other if the product of their slopes = - 1

That is,

$m_1 \times m_2 = -1$

So the slope of new line is

$-3 \times m_2 = -1\\\\m_2 = \frac{-1}{-3} = \frac{1}{3}$

$Therefore , equation \ of \ new \ line \ \\\\(y - y_1) = m_2(x - x_1) , where \ (x_1 , y_1) = (9, -6 )\\\\(y - (-6))= \frac{1}{3}(x -9)\\\\y + 6 = \frac{1}{3} x - 3\\\\y = \frac{1}{3}x -3-6\\\\y = \frac{1}{3}x -9\\\\$

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3 years ago

The entire question is un the picture

irakobra [83]

The intersection of the two equations is (1, 1/5). Since the question is asking for the value of x, x = 1.

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3 years ago

Rectangular prism A measures 6 inches by 4 inches by 5 inches. Rectangular prism B's dimensions are twice those of prism A. Find

harina [27]

The volume of <span>Rectangular prism A is 120 inches and the volume of rectangular prism is 960 inches. the volume of prism b is 8 times the size of prism A</span>

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3 years ago

Read 2 more answers

X+56<533. What is the solution of the inequality?

swat32

X<477

hope this helps<3

7 0

3 years ago

I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

5 0

3 years ago