38 divided by 817,152

Amanda used 24 grams of paint to paint a wooden cube. When it dried, she cut the cube into 8 equal cubes. How many more grams of

kari74 [83]

Answer:

<h2>Amanda needs 72 grams of paint</h2>

Step-by-step explanation:

Notice that she already painted one face of each cube, that is, 8 faces in total, and she used 24 grams for that.

Now, there remain 3 faces per cube to be painted, which means there are 24 faces.

Then, we use the rule of three, if she used 24 grams of paint for 8 faces, how much grams of paint she would need to paint 24 faces?

$24 \times \frac{24}{8}= 72 \ grams$

Therefore, Amanda needs 72 grams of paint for the unpainted surfaces.

7 0

3 years ago

36x^2+_x+4 fill in the blank

Neporo4naja [7]

Answer:

i don't know the answer lol

Step-by-step explanation:

3 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago

Please answer this is so urgent

kolezko [41]

The answer is 4565 / 63

Sorry this might be to late...

8 0

3 years ago

Need help with the problem in the photo.

noname [10]

Answer:

B (1,1) & (2,-1)

Step-by-step explanation:

This is the answer because if a line was drawn through these 2 points the slope would be the same as line QR so therefore the two would be parallel.

Hope this helps :)

8 0

3 years ago

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38 divided by 817,152​

38 divided by 817,152