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2 years ago

13

HELP!!!!What is 1/4 turned into a decimal I REALLY NEED HELP BEFORE MY TEACHER GIVES ME A BAD GRADE

2 answers:

VladimirAG [237]2 years ago

8 0

Answer:

→1/4 as a decimal is 0.25

(I hope you get this answer correct, and also hope you have a great day or night! :)).

FinnZ [79.3K]2 years ago

5 0

Answer:

0.25

Step-by-step explanation:

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Two number cubes are rolled. Each number cube has sides numbered 1 through 6.

olasank [31]

P(odd) or P(multiple of 5)
When we roll 2 number cubes

all possible outcomes of their sum are 2,3,4,5,6,7,8,9,10,11,12.(11 possible outcomes)

Out of those possible outcomes
3,5,7,9,11 are odd (5 outcomes) and ...

5 and 10 are multiples of 5 (2 outcomes)

Now, P(odd) or P(multiple of 5) really means P(odd) + P (multiple of 5) =
(If we had “and” instead of “or” we multiply)
= (5/11) +(2/11)
=7/11

7 0

3 years ago

Read 2 more answers

Luis rides his bicycle 34 mile in 5 minutes, or 112 hour, along the bike trail. Assuming he rides at a constant rate, what is hi

artcher [175]

Answer:

$408\frac{miles}{hour}$

Step-by-step explanation:

we know that

To find the speed divide the total distance by the time

so

$\frac{34}{(1/12)}=34*12=408\frac{miles}{hour}$

3 0

2 years ago

Factor the polynomial. x2 - 5xy + 6y2 A) (x - 3)(x - 2) B) (x - 6y)(x + y) C) (x - 3y)(x - 2y) D) (x + 3y)(x + 3y)

Elden [556K]

X^2 - 5xy + 6y^2 = <span>(x - 3y)(x - 2y)

answer is </span><span>C) (x - 3y)(x - 2y)

hope that helps</span>

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2 years ago

The sum of 19 data values is 2,375. What is the average of the data values?

DIA [1.3K]

Answer:

125

Step-by-step explanation:

2375/19

5 0

3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

6 0

3 years ago