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2 years ago

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There are five nickels and five dimes in your pocket. With replacing, what is the probability that you will pull a nickel the fi

rst time, a nickel the second time, and a dime the third time? Write your answer as a fraction in the simplest form explain

1 answer:

N76 [4]2 years ago

4 0

Answer:

1/8

Step-by-step explanation:

Probability of pulling a nickel the first time: 5/10

Probability of pulling a nickel the second time: 5/10 (remember that you are replacing)

Probability of pulling a dime the third time: 5/10

Total probability: 5/10 * 5/10 * 5/10 OR 1/2 * 1/2 * 1/2 = 1/8

im pretty sure this is the answer! i hope this helps! <3

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Is 3/4 bigger than 3/5

Svet_ta [14]

Yes, 3/4 is bigger than 3/5.
One way you can verify this is by drawing a bar model, and cut it into four. Color in three pieces.
Then, draw another bar model the same size as the first one, and cut it into five pieces.
Color in three pieces.
You can see that 3/4 has more shaded in area than 3/5.
Another way you can do this is by dividing the numerator by the denominator for both fractions.
Hope this helped.

8 0

3 years ago

Read 2 more answers

What is the correct answer and why show your work

Anna11 [10]

Answer:

A7.45x = y

Step-by-step explanation:

We can use a ratio to solve this problem. Take the total cost of the lunches and divide by the number of lunches.

y = total cost of lunches and

x = number of lunches

74.50 y

-------------- = ------------

10 x

Using cross products

74.5 x = 10 y

Divide each side by 10

74.5/10 x= 10y/10

7.45x = y

6 0

3 years ago

Read 2 more answers

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

What is the hypothesis of a triangle with a base of 11cm and height of 9cm

natima [27]

<u>Answer:</u>

<h2>14.21 cm</h2>

<u>Explanation:</u>

you mean the hypotenuse* lol

the hypotenuse = √(11²+9²)

the hypotenuse = √(121+81)

the hypotenuse = √(202)

the hypotenuse ≈ 14.21 cm

3 0

2 years ago

Alice and Bob are playing a game. Alice starts first. On Alice's turn, she flips a coin. If she gets a heads, she wins. If not,

trapecia [35]

Answer:

The probability that Alice wins the game= $\frac{1}{2}$

Step-by-step explanation:

We are given that Alice and Bob are playing a game .

We have to find the probability that Alice wins the game .

If Alice win when she gets head and lose when she gets tail.Bob wins when she gets tail and she lose when she gets head.

Total results in a coin=Head, tail=2

Number of head in a coin=1

Number of tail in a coin= 1

Probability is defined as the possibility of an event that occurred

$P(E)=\frac{Number\;of\;favourable\;cases}{total\;of\;cases}$

The probability that Alice wins the game= $\frac{Number\;of\;favourable\;cases}{Total\;number\;of\;cases}$

The probability that Alice wins the game= $\frac{number \;of \;heads}{Total\; results}$

The probability that Alice wins the game= $\frac{1}{2}$

8 0

3 years ago