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fgiga [73]
2 years ago
9

Find the length of CB. 5x – 3 3x + 1

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
4 0

Assumed that sides are equal

  • 5x-3=3x+1
  • 5x-3x=1+3
  • 2x=4
  • x=2

CB

  • 5(2)-3
  • 7
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Rewrite the equation x = 65 - 60p by factoring the side that contains the variable p.
grigory [225]

Answer: x=5(13-12p)


Step-by-step explanation:

Given equation: x=65-60p

\\\Rightarrowx=(5\times13)-(5\times12)p

Since 5 is the greatest common factor of 65 and 60 in the given expression.

Therefore, the above expression can be written as

x=5(13-12p)

Hence, by factoring the side that contains the variable p we have the expression x=5(13-12p).




7 0
3 years ago
Three of the angles of a polygon are
zmey [24]

Answer:

three angles of a polygon are each 105.5,the sum of the angles in the polygon is 2520. find each of the other angles if they are equal to each other. For a polygon with n sides and n angles, the sum of the measures of all the interior angles equals (n-2)180 degrees. 16-3=13

6 0
2 years ago
Plz help hurry i don’t understand
attashe74 [19]
Answer- Option 2

I hope that helps
7 0
3 years ago
when the driver is in the empty truck, the mass is 2948.35 kilogram. the mass of 1 box of paper is 22.5 kilograms. the driver de
marishachu [46]

Answer:

  0 boxes minimum

Step-by-step explanation:

The mass of the truck and paper must satisfy ...

  22.5b + 2948.35 ≤ 4700 . . . . total truck mass cannot exceed bridge limits

  22.5b ≤ 1751.65

  b ≤ 77.85

The driver can take a minimum of 0 boxes and a maximum of 77 boxes of paper over the bridge.

_____

The question asks for the <em>minimum</em>. We usually expect such a question to ask for the <em>maximum</em>.

7 0
2 years ago
1. Simplify:<br>4(4y-7y^{2})-9(5y+2)<br><br>2. Simplify:<br>24 – 4(5y – 6z) + 3y – 7z
Greeley [361]

Answer:

1)-

How to solve your question

Your question is

4(4−72)−9(5+2)

4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)

Simplify

1

Rearrange terms

4(4−72)−9(5+2)

4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)

4(−72+4)−9(5+2)

4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)

2

Distribute

4(−72+4)−9(5+2)

{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)

−282+16−9(5+2)

{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)

3

Distribute

−282+16−9(5+2)

-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)

−282+16−45−18

-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18

4

Combine like terms

2)

−17y+17z+24

See steps

Step by Step Solution:



STEP1:Equation at the end of step 1

((24 - 4 • (5y - 6z)) + 3y) - 7z

STEP2:

Final result :

-17y + 17z + 24

−282+16−45−18

-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18

−282−29−18

-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18

Solution

−282−29−18

4 0
2 years ago
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