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maks197457 [2]
2 years ago
15

Can you teach me fractions in math​

Mathematics
2 answers:
Dmitriy789 [7]2 years ago
8 0
Is there anything specific you need help with?

https://www.ducksters.com/kidsmath/fractions_introduction.php
alekssr [168]2 years ago
7 0

<em>refer to the attachment</em>

<em>thiz</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>fraction</em><em>!</em><em>!</em><em> </em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>※</em><em>※</em>

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Please! I need help!
topjm [15]

Answer:

2^1×2^3

2^8×2^−5

2^1×2^2

Step-by-step explanation:

7 0
3 years ago
Henry buys a softball for 16 dollars plus a 9% tax Ella buys a pair of shoes for 17 dollars plus a 9% tax. Enter the difference
Gwar [14]

Answer:

$1.09

Step-by-step explanation:

16*0.09 = 1.44, 16 + 1.44 = 17.44 (Henry's total cost)

17*0.09 = 1.53, 17 + 1.53 = 18.53 (Ella's total cost)

To find the difference we subtract 18.53-17.44 = 1.09 and so the difference including tax is $1.09

8 0
3 years ago
Find the lowest common denominator of p+3/p^2+7 p+10 and p+5/p^2+5 p+6
VMariaS [17]
We first need to factorize (if possible) the denominators:

we can see that p^2+7p+10=(p+2)(p+5) as 2 and 5 are two numbers whose sum is 7 and product is 10.


Similarly, we can see that p^2+5p+6=(p+3)(p+2) as 2 and 3 are two numbers whose sum is 5 and product is 6.

Thus, the expression is:

\displaystyle{  \frac{p+3}{(p+2)(p+5)} + \frac{p+5}{(p+3)(p+2)}.


Now to make the denominators equal, but to also keep them as small as possible, the common denominator must be (p+3)(p+2)(p+5).


Answer: (p+3)(p+2)(p+5).
4 0
3 years ago
Read 2 more answers
Look at the pic to awnser the question plz
grandymaker [24]
Answer:

The correct answer is 6.8.


Explanation:

63.92 ÷ 92 ≈ 6.8


Hope this helps :)



4 0
2 years ago
Write a formula to describe the sequence
Dominik [7]

Answer:

d

Step-by-step explanation:

A(n) = 1 - 0.1(n-1)

A(1) = 1- 0.1*(1-1) = 1 - 0.1*0 = 1

A(2) = 1- 0.1*(2-1) = 1 - 0.1*1 = 1- 0.1 = 0.9

A(3) = 1 - 0.1(3-1) = 1 - 0.1*2 = 1-0.2=0.8

Method:

A(1)=1

D = A(2)-A(1) = 0.9 - 1 = -0.1

A(n) = A(1)+(n-1)*d = 1 + (n-1)*(-0.1)

     = 1 - 0.1(n -1)

     

8 0
3 years ago
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