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maks197457 [2]
2 years ago
15

Can you teach me fractions in math​

Mathematics
2 answers:
Dmitriy789 [7]2 years ago
8 0
Is there anything specific you need help with?

https://www.ducksters.com/kidsmath/fractions_introduction.php
alekssr [168]2 years ago
7 0

<em>refer to the attachment</em>

<em>thiz</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>fraction</em><em>!</em><em>!</em><em> </em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>※</em><em>※</em>

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Multiply. -1/9*(-5/4) Write your answer in simplest form
s2008m [1.1K]

Answer:

\frac{5}{36}

Step-by-step explanation:

  1. -1/9 × -5/4: 9 × 4 = 36, -1 × -5 = 5
  2. Put them together: 5/36
6 0
3 years ago
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a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

4 0
3 years ago
The sum of the first three terms of geometric sequence is 14. If the first term is 2, find the possible values of the sum of the
Irina18 [472]

Geometric series are in the form of

a +a*r +a*r^2+...

Where a is the first term and r is the common ratio .

And it is given that

2 +2*r +2*r^2=14

2r^2+2r-12=0

r^2 +r-6=0

(r+3)(r-2)=0

r=-3,2

So the first five terms are

2+2(-3)+2(-3)^2+2(-3)^3+2(-3)^4  or 2+2(2)+2(2)^2+2(2)^3+2(2)^4

= 2-6+18-54+162 or 2+4+8+16+32

= 122 or 62

4 0
3 years ago
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What is the perimeter and area of the figure?
Rudiy27

Perimeter is the sum of all outside dimensions:

5 + 3 + 1 + 2 + 4 + 5 = 20cm

Area = (5 x 5) - (2*1) = 25 - 2 = 23 cm^2

7 0
3 years ago
Please provide all steps given to find the answer. Thanks!!!<br> Simplify: 5(2x+9)²
gulaghasi [49]

Answer:

20x²+180x + 405

Step-by-step explanation:

Follow PEMDAS to know what you do first

square (2x + 9) by foiling

(2x+9) (2x + 9)

= 4x²+ 36x + 81

Multiply by 5

20x²+180x + 405

4 0
3 years ago
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