Answer:

Step-by-step explanation:
- -1/9 × -5/4: 9 × 4 = 36, -1 × -5 = 5
- Put them together: 5/36
Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
Geometric series are in the form of

Where a is the first term and r is the common ratio .
And it is given that




r=-3,2
So the first five terms are

= 2-6+18-54+162 or 2+4+8+16+32
= 122 or 62
Perimeter is the sum of all outside dimensions:
5 + 3 + 1 + 2 + 4 + 5 = 20cm
Area = (5 x 5) - (2*1) = 25 - 2 = 23 cm^2
Answer:
20x²+180x + 405
Step-by-step explanation:
Follow PEMDAS to know what you do first
square (2x + 9) by foiling
(2x+9) (2x + 9)
= 4x²+ 36x + 81
Multiply by 5
20x²+180x + 405