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tigry1 [53]
2 years ago
15

What is the value of x in the geometric sequence x,3,-1/3

Mathematics
1 answer:
GalinKa [24]2 years ago
6 0

The value of the unknown variable x by virtue of the geometric sequence given in the task content is; -27.

<h3>What is a geometric sequence and what is the value of x in the sequence given?</h3>

It follows from the task content above that the variable given above is a member of the geometric sequence.

Hence, since it follows from convention that the geometric sequence in discuss has same common difference across each successive term and hence , we have;

3/x = (-1/3) ÷ 3

x = -27.

Therefore, the value of the unknown variable x by virtue of the geometric sequence given in the task content is; -27.

Read more on geometric sequence;

brainly.com/question/1509142

#SPJ1

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vampirchik [111]
The triangle inequality applies.

In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.

In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.

The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
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3 years ago
Find the value of x for which ABCD must be a parallelogram.
kolbaska11 [484]
4x-1=x+26
3x-1=26
3x=27
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4 years ago
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Vadim26 [7]
Slope=5. The change in y is +5and the change in x values is +1. 5/1=5
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3 years ago
Consider the following system of equations: 10 + y = 5x + x2 5x + y = 1 The first equation is an equation of a . The second equa
aleksley [76]

Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.

Explanation:

The first equation is,

10+y=5x+x^2

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.

The second equation is,

5x+y=1

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.

Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.

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An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
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