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11Alexandr11 [23.1K]
3 years ago
7

Which statement best describes the role that gravity played in the formation of our solar system?

Chemistry
2 answers:
Anna35 [415]3 years ago
8 0
<span>d*Gravity pulled particles of dust and gas together to form planets.

hope this helps</span>
pochemuha3 years ago
8 0

The correct answer is D. Gravity pulled particles of dust and gas together to form planets.

Explanation:

Gravity is a force of attraction that acts in all universe, and makes objects with more matter attract objects with less matter. This force played an important role in the formation of our solar system. Because it is believed after the big bang occurred, there was a massive cloud of dust, gas, and particles (nebula) and due to the force exerted by gravity, these particles were pulled together forming clumps of different sizes and characteristics that were later the planets, moons and other structures that remain until today. Also due to the force of gravity the sun was formed and planets orbit around it. According to this, the role of gravity in the formation of our solar system was gravity pulled particles of dust and gas together to form planets.

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PLEASE ANSWER
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Answer:

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Explanation:

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3 years ago
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3 years ago
The pH of a 0.78M solution of 4-pyridinecarboxylic acid HC6H4NO2is measured to be 2.53.Calculate the acid dissociation constant
nika2105 [10]

Answer : The value of acid dissociation constant is, 1.1\times 10^{-5}

Solution :  Given,

Concentration pyridinecarboxylic acid = 0.78 M

pH = 2.53

First we have to calculate the hydrogen ion concentration.

pH=-\log [H^+]

2.53=-\log [H^+]

[H^+]=2.95\times 106{-3}M

Now we have to calculate the acid dissociation constant.

The equilibrium reaction for dissociation of (weak acid) is,

                        HC_6H_4NO_2\rightleftharpoons C_6H_4NO_2^-+H^+

initially conc.         0.78                0             0

At eqm.               (0.78-x)              x             x  

The expression of acid dissociation constant for acid is:

k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}

As, [H^+]=[C_6H_4NO_2^-]=x

So,  x=2.95\times 106{-3}M

Now put all the given values in this formula ,we get:

k_a=\frac{(x)\times (x)}{(0.78-x)}

k_a=\frac{(2.95\times 106{-3})\times (2.95\times 106{-3})}{(0.78-2.95\times 106{-3})}

K_a=1.1\times 10^{-5}

Therefore, the value of acid dissociation constant is, 1.1\times 10^{-5}

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