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Rashid [163]
3 years ago
11

A spinner is divided into blue green and red part.George spin the spinner 300 times. It lands 91 times on blue 107 times on gree

n and 102 times on red dot based on this data, what is the estimated probability of the spinner landing on red?
Mathematics
1 answer:
Fed [463]3 years ago
3 0
Estimated probability=number of outcomes in question/divided by total number of trials

ep=102/300

ep=51/150  (34%)
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Which expression is equal to 2X^2+7<br> (Simplify)
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One of the legs of a right triangle measures 7 cm and its hypotenuse measures 12 cm.
Oksana_A [137]

Answer:

AC ≈ 9,7sm

Step-by-step explanation:

AB=7  One side of a right triangle

BC=12  Hypotenuse of a right triangle

AC=?=x  The other side of a right triangle

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x²=144-49

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3 0
2 years ago
200-[(50-4)×3+5]<br><img src="https://tex.z-dn.net/?f=200%20-%20%28%2850%20-%204%29%20%5Ctimes%203%20%2B%205%29" id="TexFormula1
lbvjy [14]
200 - [ ( 50 - 4 ) × 3 + 5 ]
= 200 - [ 46 × 3 + 5 ]
<Put brackets around the 2 number that enclose the times sign as a reminder to do that first>
= 200 - [ ( 46 × 3 ) + 5 ]
= 200 - [ 138 + 5 ]
= 200 - (143)
= 57

Hope this helps!
3 0
3 years ago
A town in east Texas recieved 10 inches of rain in two weeks. If it kept raining at this rate for a 31-day month, how much rain
Gelneren [198K]
The best way to approach this problem is to find out how much fell in week. As you know what two weeks is, you simply have to halve this, giving you that one week is 5 inches of rain. One you have this, you can multiply this by 4 (as this will give you 4 weeks, or 28 days), and this gives you 20 inches in 28 days. You should then find the odd three days. If you divide 5 by 7, this will give you the rain fall in one day. 5/7= 0.8 inches per day. You then have top multiply this by 3 (as you've got three odd days), and this gives you 2.4. You then have to add together 2.4 and 20, giving you 22.4
Therefore, if the rain continued to fall at the same rate for 31 days, it would receive 22.4 inches of rain.
Hope this helps :) 
8 0
3 years ago
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