Multiply the first equation with (-1)
you should get this
-6r + 3t = -6
6r + 8t = -16
start to eliminate
11t = -22
divide by 11
t = -2
substitute
6r - 3(-2) = 6
6r + 6 = 6
6r = 6 - 6
6r = 0
r=0
Answer:
![\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7By%3D-%5Cdfrac%7B1%7D%7B3%7Dx-%5Cdfrac%7B10%7D%7B3%7D%5Cto%20x%2B3y%3D-10%7D)
Step-by-step explanation:
The slope-intercept form of an equation of a line:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
The formula of a slope:
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
We have the points (5, -5) and (-4, -2).
Substiute:
![m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B-2-%28-5%29%7D%7B-4-5%7D%3D%5Cdfrac%7B-2%2B5%7D%7B-9%7D%3D%5Cdfrac%7B3%7D%7B-9%7D%3D-%5Cdfrac%7B1%7D%7B3%7D)
Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:
![-5=-\dfrac{1}{3}(5)+b](https://tex.z-dn.net/?f=-5%3D-%5Cdfrac%7B1%7D%7B3%7D%285%29%2Bb)
<em>add 5/3 to both sides</em>
![-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}](https://tex.z-dn.net/?f=-%5Cdfrac%7B15%7D%7B3%7D%2B%5Cdfrac%7B5%7D%7B3%7D%3Db%5C%5C%5C%5C-%5Cdfrac%7B10%7D%7B3%7D%3Db%5Cto%20b%3D-%5Cdfrac%7B10%7D%7B3%7D)
Finally we have the equation of a line in the slope-intercept form:
![y=-\dfrac{1}{3}x-\dfrac{10}{3}](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B1%7D%7B3%7Dx-%5Cdfrac%7B10%7D%7B3%7D)
Convert to the standard form <em>(Ax + By = C)</em>:
<em>multiply both sides by 3</em>
<em>add x to both sides</em>
![x+3y=-10](https://tex.z-dn.net/?f=x%2B3y%3D-10)
Answer:
X < 9
The hallow circle means just greater than or less than
The numberline is pointing downwards showing that 9 is greater than x(unknown value)
The point is also on 9
I. H o p e It. R I g h t.
(x - 9) (x-3)
The error interval of the perimeter is 6.1 cm ≤ p < 6.15 cm
<h3>How to determine the error of interval?</h3>
The perimeter is given as:
P = 6.1 cm to 1 decimal place
The smallest number that can be approximated to 6.1 is 6.05, while the largest number is less than 6.15
This means that the interval is:
6.1 cm ≤ p < 6.15
Read more about error interval at:
brainly.com/question/16810055
#SPJ1