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3 years ago

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Suppose that the function f(x)=4x-2 represents the cost to rent x movies a month from an internet movie club. Laticia now has $1

2. How many more dollars does Laticia need to rent 5 movies next month?

1 answer:

Simora [160]3 years ago

5 0

Not really sure i am sorry

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1. Consider an athlete running a 40-m dash. The position of the athlete is given by , where d is the position in meters and t is

sasho [114]

There is some information missing in the question, since we need to know what the position function is. The whole problem should look like this:

Consider an athlete running a 40-m dash. The position of the athlete is given by $d(t)=\frac{t^{2}}{6}+4t$ where d is the position in meters and t is the time elapsed, measured in seconds.

Compute the average velocity of the runner over the intervals:

(a) [1.95, 2.05]

(b) [1.995, 2.005]

(c) [1.9995, 2.0005]

(d) [2, 2.00001]

Answer

(a) 6.00041667m/s

(b) 6.00000417 m/s

(c) 6.00000004 m/s

(d) 6.00001 m/s

The instantaneous velocity of the athlete at t=2s is 6m/s

Step by step Explanation:

In order to find the average velocity on the given intervals, we will need to use the averate velocity formula:

$V_{average}=\frac{d(t_{2})-d(t_{1})}{t_{2}-t_{1}}$

so let's take the first interval:

(a) [1.95, 2.05]

$V_{average}=\frac{d(2.05)-d(1.95)}{2.05-1.95}$

we get that:

$d(1.95)=\frac{(1.95)^{3}}{6}+4(1.95)=9.0358125$

$d(2.05)=\frac{(2.05)^{3}}{6}+4(2.05)=9.635854167$

so:

$V_{average}=\frac{9.6358854167-9.0358125}{2.05-1.95}=6.00041667m/s$

(b) [1.995, 2.005]

$V_{average}=\frac{d(2.005)-d(1.995)}{2.005-1.995}$

we get that:

$d(1.995)=\frac{(1.995)^{3}}{6}+4(1.995)=9.30335831$

$d(2.005)=\frac{(2.005)^{3}}{6}+4(2.005)=9.363335835$

so:

$V_{average}=\frac{9.363335835-9.30335831}{2.005-1.995}=6.00000417m/s$

(c) [1.9995, 2.0005]

$V_{average}=\frac{d(2.0005)-d(1.9995)}{2.0005-1.9995}$

we get that:

$d(1.9995)=\frac{(1.9995)^{3}}{6}+4(1.9995)=9.33033358$

$d(2.0005)=\frac{(2.0005)^{3}}{6}+4(2.0005)=9.33633358$

so:

$V_{average}=\frac{9.33633358-9.33033358}{2.0005-1.9995}=6.00000004m/s$

(d) [2, 2.00001]

$V_{average}=\frac{d(2.00001)-d(2)}{2.00001-2}$

we get that:

$d(2)=\frac{(2)^{3}}{6}+4(2)=9.33333333$

$d(2.00001)=\frac{(2.00001)^{3}}{6}+4(2.00001)=9.33339333$

so:

$V_{average}=\frac{9.33339333-9.33333333}{2.00001-2}=6.00001m/s$

Since the closer the interval is to 2 the more it approaches to 6m/s, then the instantaneous velocity of the athlete at t=2s is 6m/s

8 0

3 years ago

Factor the GCF: −6m2 + 18m − 36.

leva [86]

The first option is the right one.

You have to find the greates common divisor of the coefficientes, which is -6 and then divide each momomial with lead to: -6 (m^2 + -3m + 6).

You can verifiy the result by multiplying -6 times the polynomial inside the parenthesis, using the distributive property.

4 0

4 years ago

Read 2 more answers

Drag the numbers to order them from greatest to least, with the greatest at the top.

Savatey [412]

10pi

9.92749....

square root of 101

0.99853....

6 0

3 years ago

Read 2 more answers

An office manager buys 34 chairs for the new office. Each chair costs $205. What is the total amount the office manager pays for

alekssr [168]

Answer:

so each chair will cost 205

205 will be our cost C this is our dependent due to the entire cost being base on how many chairs that will get order

the independent variable will be how many chairs that will be ordered and there are 34 chairs being ordered

34*205= 6970

the total cost will be 6970

8 0

3 years ago

For the graph of the function below, identify the axis of symmetry, vertex and formula for the function

zhannawk [14.2K]

Well the first obvious thing is that the axis of symmetry is 0.5, so we can automatically cross out (C).

All the answers have the correct vertex, so lets find the formula for the function.

Fortunately, from my point of view, I can see two points that have their coordinates as integers, (-1, -3) and (2, 3), we can plug these into the already given "formulas" in the options (A), (B), and (D).

Out of the three choices, the formula in option (D) satisfies both coordinates, thus option (D) is correct.

3 0

4 years ago