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ella [17]
1 year ago
5

Graph the line y+3x=-3​

Mathematics
1 answer:
ivanzaharov [21]1 year ago
3 0

Answer:  y = -3x-3 (Choose values for x)

Step-by-step explanation:

1st change the equation to y = mx+b form

In order to change the equation to y = mx+b form subtract the 3x to both sides.
The equation now becomes y = -3x-3

2nd we can either choose values for x such has (-2,-1,0,1,2) and plug in those values into our equation y = -3x-3
For example, if we plug in x= -2 we get y= -3(-2)-3 which becomes y =3. We then plot the point (-2,3) because -2 is our x coordinate and 3 is our y coordinate.
Or we can plug the equation into a calculator that will graph the equation for you.

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The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.

In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.

The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)

E = 2% = 0.02

Confidence level = 90%

Now, the proportion is not given so adopt nominal (p-vector) = 0.05

The critical value at CL of 90% is 1.645.

Thus, making n the subject,

n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)

n = 1.645²((0.5 × 0.5) ÷ 0.02²)

n = 1691.266

n ≈ 1691

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For a snack, Sameer ate a plum with 32 calories and several strawberries with 4 calories each. If the total number of calories i
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3 years ago
Read 2 more answers
URGENT PLEASE HURRY I'M RUNNING OUT OF TIME!!!!!
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2.15
1hr is 60 min so
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3 years ago
Write an expression for the measurement of angle L using the measurement of angle C found in part C
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Step-by-step explanation:

3 0
2 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
3 years ago
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