The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.
In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.
The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)
E = 2% = 0.02
Confidence level = 90%
Now, the proportion is not given so adopt nominal (p-vector) = 0.05
The critical value at CL of 90% is 1.645.
Thus, making n the subject,
n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)
n = 1.645²((0.5 × 0.5) ÷ 0.02²)
n = 1691.266
n ≈ 1691
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2.15
1hr is 60 min so
60÷15=4
45miles×2hrs=90
45÷4=11.25
90+11.25=101.25 miles
101.25 miles÷ 25 miles per gallon= 4.05 gallons
4.05 gallons× $2.75 per gallon= $11.1375
$11.1375= $11.14
Alicia spends $11.14 on gas to get to work
Answer:
180’ - 130’
Step-by-step explanation:
Answer:

Step-by-step explanation:
Using the addition formulae for cosine
cos(x ± y) = cosxcosy ∓ sinxsiny
---------------------------------------------------------------
cos(120 + x) = cos120cosx - sin120sinx
= - cos60cosx - sin60sinx
= -
cosx -
sinx
squaring to obtain cos² (120 + x)
=
cos²x +
sinxcosx +
sin²x
--------------------------------------------------------------------
cos(120 - x) = cos120cosx + sin120sinx
= -cos60cosx + sin60sinx
= -
cosx +
sinx
squaring to obtain cos²(120 - x)
=
cos²x -
sinxcosx +
sin²x
--------------------------------------------------------------------------
Putting it all together
cos²x +
cos²x +
sinxcosx +
sin²x +
cos²x -
sinxcosx +
sin²x
= cos²x +
cos²x +
sin²x
=
cos²x +
sin²x
=
(cos²x + sin²x) = 