1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVETLANKA909090 [29]
3 years ago
5

(brainliest) please help!!

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

(-1, 3)

Step-by-step explanation:

You might be interested in
A dog collar was originally priced at $5 but went on sale for 20% off. If Vince bought the dog collar and paid 9% sales tax, how
Vlada [557]

Answer:$4.36

Step-by-step explanation:

5(0.8)= 4

4(1.09) = $4.36

3 0
3 years ago
When y=-2, what kind of line does it have horizontal or vertical
Rashid [163]

Answer: Horizontal

Step-by-step explanation: The equation <em>y = -2</em> can be thought of as y = 0x - 2. So our line has a slope of 0 and a y-intercept of -2.

To graph it, we start with the y-intercept, down 2 units on the y-axis. Now, if the slope of a line is 0, then the line must be flat or horizontal.

So we just draw a horizontal line through the y-intercept of -2.

In fact, when the equation of any line reads y = a number, it's graph will always be a horizontal line. For example, y = 3, y = -10, y = -8 and so on.

Image provided below.

8 0
3 years ago
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
NEED HELP ON THIS PLEASE! Oregon Trail: Percents.
harina [27]

1845-1846

118->148

148-118 = 30 = change

percent

30/118 ≈ 25.4%

1846-1847

148->139

148-139 = 9 = change

percent

9/148 ≈ 6%

1847-1848

139->151

151-139 = 12 = change

percent

12/139 ≈ 8.6%


Hope this helped :)

5 0
2 years ago
What is the answer = 8w- 8 - 6w = 4w - 7<br> w= ??
ololo11 [35]

Answer:

<em>- 1/2     (or - 0.5) </em>

Step-by-step explanation:

so first, simplify by combining like terms.

so 8w-6w = 2w

so now we have

2w - 8 = 4w - 7

now we have to get the w's to one side of the equation so we can solve for it. so that mean we have to subtract 2w from both sides. 2w - 2w is 0. and then 4w - 2w = 2w. so now we have

-8 = 2w - 7

then to slowly start isolating w, add 7 to both sides of th equation. so now its

-1 = 2w

finally to get w by itself divide 2 from both sides.

and the answer is

-\frac{1}{2} = w

5 0
3 years ago
Other questions:
  • Using benchmarks to measure length of a car customary unit
    10·1 answer
  • What Is 1,270 rounded to the nearest hundred?
    12·1 answer
  • On eight book shelves there are 44 books per shelf. How many books are there altogether? If 1/4 of these books are novels, how m
    6·1 answer
  • The volume of a cube is 1,728 cubic inches, find the side length of each of its sides.
    14·1 answer
  • I need to know the answer.
    7·2 answers
  • A company that makes mirrors sends their slightly flawed products to a discount store. This week, the company sent four mirrors
    6·2 answers
  • Charlie has been given a list of 4 bands and asked to place a vote. His vote must have the names of his favorite and second favo
    12·1 answer
  • Find the missing number 1:2 = 3: ____ <br><br>       A. 1   B. 2   C. 6   D. 3
    15·2 answers
  • A triangle cannot have more than _________ right angle.​
    7·2 answers
  • What is the simplest form of 60 : 120?​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!