Answer:
<em>The highest grade metamorphic rocks will be formed at high temperatures and high pressures.</em>
Explanation:
Metamorphic rocks can be described as the type of rocks which are formed by a change in the form of the existing rocks. In other words, metamorphosis of igneous, sedimentary or existing metamorphic rocks leads to the production of metamorphic rocks. High temperature and pressure are required by the rocks to change its form and develop into metamorphic rocks. Temperatures usually more than 320 degree Celsius are required for high-grade metamorphism.
A drop in intercourse hormones in a woman's bloodstream along with cessation of ovulation and menstruation signals: menopause.
Menopause is a factor in time 12 months after a woman's last period. The years leading up to that point, when women may additionally have changes in their monthly cycles, warm flashes, or different symptoms, are known as the menopausal transition or perimenopause. The menopausal transition most often starts between a while forty five and 55.
<h3 /><h3>What occurs to a person throughout menopause?</h3>
Your physique goes through a lot of adjustments throughout menopause. There are extreme shifts in your hormone levels, you might also not sleep nicely because of hot flashes and you may also ride mood swings. Anxiety and fear may want to additionally be at play all through this time. All of these elements can lead to depression.
Learn more about menopause here:
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brainly.com/question/3588586</h3><h3 /><h3>#SPJ4</h3>
Answer:
0.9342
Explanation:
The Hardy-Weinberg equation states that p² + 2pq + q² = 1,
where p is the frequency of the dominant 'normal' (n) allele and q is the frequency of the recessive 'albino' (a) allele in the population, while q² represents the frequency of the homo-zygous albino genotype (aa), p² represents the frequency of the homo-zygous normal genotype (nn) and 2pq represents the frequency of the heterozygous genotype (na).
In this case, the frequency of individuals in the population that have the genotype aa (q²) is equal to 26/6000 = 0.004333. In consequence, q is equal to √ 0.004333 = 0.0658.
Moreover, the allele frequency of the normal (n) allele p is equal to 1 - q = 1 - 0.0658 = 0.9342, so p² (nn) = (0.9342)² = 0.8727.
Finally, the frequency of the heterozygous genotype (na) is 2pq = 2 x 0.9342 x 0.0658 = 0.123.
I believe the answer is c
