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Elza [17]
2 years ago
8

If a rectangle is not a square, what is the greatest number of lines of symmetry that can be drawn?

Mathematics
1 answer:
eimsori [14]2 years ago
5 0

Answer: B

Step-by-step explanation: what I did was I drew a square and folded it if both sides matched i knew that that was a line of symmetry

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Line WY is an altitude in triangle WXZ. If ΔYWZ ~ ΔYXW, what is true about XWZ? XWZ is an obtuse angle. XWZ is a right angle. XW
topjm [15]
<span>In triangle WXZ,

Line WY is an altitude (as shown in the attached picture)
Now, it is given that:
</span><span>If ΔYWZ ~ ΔYXW
</span>∠WXY = ∠WZY
<span>
Then, we can also conclude 
</span>∠WYX = ∠WYZ = 90°....(1) (because WY is the altitude)

Now, in any triangle, the sum of all the three angles is 180.

In triangle, WXY, ∠WYX = 90° (From 1)
Therefore, WXY + XWY = 90°

Similarly, in WZY.

Hence, we conclude that XWZ is a right angle.

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4 years ago
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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down; drag it into the corre
Alex777 [14]
8x^3 -5x^2 + 8x + 9+5x^3 + 3x^2 - 5x + 4 = 
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13x^3-2x^2+3x+13
3 0
4 years ago
I hate orange juice popping do you what do you like
pychu [463]

Answer:

what even is this question lol

Step-by-step explanation:

4 0
4 years ago
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VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
4 years ago
Can you also explain how you got the answer
Alja [10]

Answer:

I recoment using the formula because its different ways its taught

Step-by-step explanation:

maybe look up different formula's

5 0
3 years ago
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