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Alexeev081 [22]
1 year ago
5

Find the slope of a line parallel to the line that crosses ( 3 , − 2 ) and the y -intercept is ( 0 , − 3 ) . I finally figured o

ut how to write my equations in slope intercept form and NOW this pops up, can someone please explain it to me
Mathematics
1 answer:
mamaluj [8]1 year ago
8 0

Answer:

y = 1/3x - 3

Step-by-step explanation:

We can find the equation of the line, by finding the slope and combine with our y-intercept (-3).

We need to use the slope formula to find the slope.

Thus, we have (-3 - (-2)) / 0 - 3 = -1/-3 = 1/3

So our equation is y = -1/3x - 3

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3 years ago
14x + 6 = 5x - 3 with solution
Schach [20]

hey there

the answer is

14x + 6 = 5x + -3


6 + 14x = 5x + -5

6 + 14x = -3 + 5x


6 + 14x + -5x = -3 + 5x + -5x


Combine like terms: 14x + -5x = 9x

6 + 9x = -3 + 5x + -5x


Combine like terms: 5x + -5x = 0

6 + 9x = -3 + 0

6 + 9x = -3

6 + -6 + 9x = -3 + -6


Combine like terms: 6 + -6 = 0

0 + 9x = -3 + -6

9x = -3 + -6


Combine like terms: -3 + -6 = -9

9x = -9


Divide each side by '9'.

x = -1


Simplifying

x = -1

thank you

OFFICIALLYSAVAGE2003

5 0
3 years ago
If p/q=q/r then prove that p3+q3+r3=(1/p3+1/q3+1/r3)p2q2r2​
luda_lava [24]

Hope you could understand.

If you have any query, feel free to ask.

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