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ANTONII [103]
3 years ago
5

What integer represent 10 degrees above zero?

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

10

Step-by-step explanation:

Hope this helps

kumpel [21]3 years ago
5 0

Answer:

 10

Step-by-step explanation:

an integer is an opposite but if it is above zero it is a positive number and and integer of a positive number is another positive number

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PLEASE HELP WORTH 99 POINTS AND CORRECT ANSWER WILL GET BRAINLIEST
Soloha48 [4]

Hello!

I believe the answers are:

A) The vertex is (1, −6)

C) The graph has a minimum.

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7 0
3 years ago
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Solve the inequality 7y-34 ≤ 8
Vlad1618 [11]
Answer:

Explanation: start by adding 34 to both sides to make the variable stand alone giving you
7y is greater than or equal to 42
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8 0
3 years ago
Please I’ve attached the question can you help me
Andreyy89

Answer:

1. <em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. <em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. D. I, II and III.

Step-by-step explanation:

U = {21, 22, 23, ..., 64}

A prime number is a number that can be divided only by 1 and itself.

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B = {24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

C = {6, 10, 12, 15, 20, 30, 60}

1. Find <em>n</em>[(A U B) - C]

<em>n</em>(A U B) = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63}

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63} - {6, 10, 12, 15, 20, 30, 60}

Since only 30 and 60 are common to <em>n</em>(A U B) and C, we therefore remove them it and have:

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. Find <em>n</em>[(A - B) U C]

To get <em>n</em>(A - B) we remove all the elements of B in A. Since there are no common elements between A and B, we therefore have:

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

C = {6, 10, 12, 15, 20, 30, 60}

Therefore, we have:

<em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. Which of the following is/are true?

I. A ∩ B = A ∩ C

A ∩ B = ∅

A ∩ C = ∅

Therefore, A ∩ B = A ∩ C is true.

II. A - B = A - C

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

A - C = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

Therefore, A - B = A - C is true.

III. A ∩ (B ∪ C) = ∅

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B U C = {6, 10, 12, 15, 20, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

Therefore, A ∩ (B ∪ C) = ∅ is true.

Therefore, the correct option is D i.e. I, II and III are true.

4 0
3 years ago
What is the factorisation of x2 + 2x
nadezda [96]

The GCF: x

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5 0
1 year ago
How to solve this plss frac{(\sqrt{(3)})^{5}}{((\sqrt{(3)})^{-4})}=(\sqrt{(3)})^{(2k+1)​
dusya [7]

Answer:

k = 4

Step-by-step explanation:

Given equation:

\dfrac{(\sqrt{3})^{5}}{(\sqrt{3})^{-4}}=(\sqrt{3})^{(2k+1)}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies (\sqrt{3})^{(5-(-4))}=(\sqrt{3})^{(2k+1)}

\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}

\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):

\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}

\implies 9=2k+1

\implies 2k=8

\implies k=4

6 0
2 years ago
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