Need help with number 15 please help

What is the solution to this system of equations?<br> x = 12 − y<br> 2x + 3y = 29

Elenna [48]

Let’s arrange the fist equation
x+y=12
2x+3y=29

Multiply equation 1 by 2
So it will be

2x+2y=24

Subtract eq 1 from eq 2

2x+3y=29
2x+2y=24
—————-
Y =5

Put value of y in eq 1

2x+2y=24
2x +10= 24
2x= 24-10
2x= 14
x=14/2
x=7

S.S= (7,5)

8 0

2 years ago

Read 2 more answers

Identifying Possible Triangles

Masja [62]

Answer:

3rd triangle can be constructed with dimensions 2,6,7.

Step-by-step explanation:

sum of any two sides > third side.

difference of any two sides < third side

1.

8+5=13 not >14 (no triangle.)

2.

7+8=15 not >15 (no triangle)

3.

2+6=8>7

2+7=9>6

7+6=13>2

7-2=5<6

7-6=1<2

6-2=4<7

so it is a triangle.

4.

6+3=9 not >10 (not a triangle)

5 0

2 years ago

Evaluate the expression for the given value of the variuble with step by step explanation

GaryK [48]

Substitute the value of b = -2 to the expression

$-4b-8+(-1)-b^2+2b^3=2b^3-b^2-4b-8-1=2b^3-b^2-4b-9\\\\2(-2)^3-(-2)^2-4(-2)-9=2(-8)-4+8-9=-16-4+8-9=-21$

7 0

3 years ago

PLEASE HELP!!!!! 3, 8, 13, 18, 23, ....<br><br> The recursive formula for this sequence is:

rodikova [14]

Answer:

a₈ = 37

Step-by-step explanation:

The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .

The recursive formula for the sequence is: $a_n = a_{n - 1} + 5$

Here, $a_n$ represents the $n^{th}$ of the sequence.

And, $a_{n - 1}$ represents the $(n - 1)^{th}$ of the sequence.

'+5' denotes that '5' is added to the $(n - 1)^{th}$ term to get the $n^{th}$ term. In other words, the difference between two consecutive numbers in the sequence is 5.

Now, we are asked to find a₈ i.e., n =8.

Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.

So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.

⇒ a₆ = 23 + 5 = 28.

⇒ a₇ = 28 + 5 = 32.

⇒ a₈ = 32 + 5 = 37.

Therefore, the $8^{th}$ term of the sequence is 37.

8 0

2 years ago

Square root of 32 x square root of 1 over 18

lisov135 [29]

<h3>Solution:</h3>

$\sqrt{32} \times \sqrt{ \frac{1}{18} } \\ = \sqrt{32} \times \frac{ \sqrt{1} }{ \sqrt{18} } \\ = \sqrt{32} \times \frac{1}{ \sqrt{18} } \\ = \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} } \\ = \frac{ \sqrt{ {2}^{2} \times {2}^{2} \times 2} }{ \sqrt{2 \times {3}^{2} } } \\ = \frac{2 \times 2 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4}{3}$

<h3>Answer:</h3>

$\frac{4}{3}$

<h3>Hope it helps...</h3>

ray4918 here to help

7 0

2 years ago