Answer:
; minimum
Step-by-step explanation:
Given:
The function is, 
The given function represent a parabola and can be expressed in vertex form as:
The vertex form of a parabola is 
, where, 
is the vertex.
So, the vertex is .
In order to graph the given parabola, we find some points on it.
Let 
So, the points are 
.
Mark these points on the graph and join them using a smooth curve.
The graph is shown below.
From the graph, we conclude that at the vertex , it is minimum.
Answer:
D = 9sin(2π(t + a)/24) + 45
Step-by-step explanation:
Let's find the average temperature;
(54 + 36)/2 = 45°
Amplitude = 54 - 45 = 9
From the wave equation, we can write the temperature as;
D = 9sin(2π(t + a)/24) + 45
Where;
D is the temperature
t is the time in hours after midnight
a is a "phase" that is used to set the time at which temperature(D) occurs
Answer:
419,108 is divisible by 4
Step-by-step explanation:
419,108 is divisible by 4, if there is an integer 'n' such that 419,108 = 'n' × 4.
A) 0.59 uses 2 sig figs
B) 100.6 uses 4 sig figs (the zeros in this case are significant)
C) 98.42 uses 4 sig figs
D) 1.045 uses 4 sig figs (the zero is between other sig figs so it's significant)
Every choice but choice A has 4 sig figs. So the answers are B, C, and D
Answer:
A) mPQ = 71º
B) mSR = 161º
C) mQRT = 199ª
D) mPSR = 270º
E) mPS = 109º
Step-by-step explanation:
We know that mST is 19º and QR is also 19º because they're opposite angles. We also know that angle PUR is 90º.
If we subtract 19º from 90º we get 71º for mPQ.
We also know that TR is a 180º angle. Using this if we take 19º from 180º we're left with 161º for mSR.
Using the 180º from angle TR, as well as the 19º from mQR we know that mQRT has to be 199º.
A circle is 360º and a right angle is 90º. That means that mPSR is 270º.
Knowing that TR is 180º and that PR is 90º, PTº must be supplementary making it also 90º. Adding the 19º from ST to the 90º from TP we know that PS is 109º
