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Scorpion4ik [409]
3 years ago
14

How to solve a system of equations using elimination

Mathematics
2 answers:
mestny [16]3 years ago
3 0
In order to use the elimination<span> method, you have to create variables that have the same coefficient—then you can eliminate them. Multiply the top </span>equation<span> by 5. Next add the</span>equations<span>, and </span>solve<span> for y. Substitute y = 10 into one of the original </span>equations<span> to find x</span>
dimulka [17.4K]3 years ago
3 0

To solve a system of equations by addition, also called elimination, the goal is to cancel out one of the variables by adding the equations together. However, in some cases, you will need to multiply one or both of the equations by a number in order to create a scenario where one of the variables will cancel out when the equations are added together. As long as you cancel a variable out, you will be able to add the equations together and solve for the variable. If you find one variable, you can find the other one easily.

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Step-by-step explanation:

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2 years ago
Solve for x in the equation x squared + 2 x + 1 = 17.
Papessa [141]

Answer:

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

Step-by-step explanation:

given equation

x^2 +2x +1 = 17

subtracting 17 from both sides

x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\

the solution for quadratic equation

ax^2 + bx + c = 0 is given by

x = x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a

________________________________

in our problem

a = 1

b = 2

c = -16

x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4  + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x =  ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\

thus value of x is

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

3 0
2 years ago
Solve for x. (7x+4)+(8x-4)
Iteru [2.4K]

Answer:

x=15

Step-by-step explanation:

thats what i got

Hope this helps!

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Answer:

1/2

Step-by-step explanation:

7 0
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