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Elina [12.6K]
2 years ago
14

What is the general equation of a tilted ellipses not centered at the origin?

Mathematics
1 answer:
Nastasia [14]2 years ago
3 0

Answer:

Please see the photo attached below.

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]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf
Anna35 [415]

Answer:

\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}} best completes this argument

Step-by-step explanation:

Circumference of circle =\pi \cdot d

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to \frac{360^{\circ}}{n^{\circ}}

So, Number of sectors =  \frac{360^{\circ}}{n^{\circ}}

The arc length of each sector is the circumference divided by the number of sectors

\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}

Diameter d = 2r (r = radius)

\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}

Option b is true

Hence\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}} best completes this argument

7 0
4 years ago
Pls help I dont understand. Find the inverse of this function.
lisov135 [29]

In the inverse we replace the place of x by y .

g(x) =  \sqrt[3]{x}  - 3 \\  \\ x =  \sqrt[3]{y}  - 3 \\  \sqrt[3]{y}  = x + 3 \\ y =  {(x + 3)}^{3}  \\ y =  {(x + 3)}^{2} (x + 3) \\ y =  ({x}^{2}  + 6x + 9)(x + 3) \\ \\  y =  {x}^{3}  + 6 {x}^{2}  + 9x + 3 {x}^{2}  + 18x + 27 \\  \\ y =  {x}^{3}  + 9 {x}^{2}  + 27x + 27 \\   \\ \\ g(x)^{ - 1}  =  {x}^{3}  + 9 {x}^{2}  + 27x + 27

I hope I helped you^_^

8 0
3 years ago
Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

6 0
3 years ago
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1/3
Think of a pizza. 2/3 of a pizza is more than 1/3 of a pizza

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