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san4es73 [151]
4 years ago
9

Help plzz i need the answer fast

Mathematics
2 answers:
Kisachek [45]4 years ago
7 0
-2 and 3 are your correct answers
ozzi4 years ago
4 0

Answer:yes you are correct but it’s hard to explain why

Step-by-step explanation:

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Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}

with determinant |J| = 12, hence the area element becomes

dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
HELP PLEASE!!!!!!!!!​
Rudiy27

Answer:

15 hight and 6 langth

Step-by-step explanation:

its just u measure the hight and the langht is half of 12

5 0
3 years ago
Write the first five terms of the sequence in which the nth term is
ziro4ka [17]

Answer:

C) 2,6,24,120,720

Step-by-step explanation:

Here the n-th term An = \frac{(n +2)!}{n + 2}

A1 is the first term

A1 = (1 + 2)!/(1 + 2)

= 3!/3

A1 = 2

A2 is the second term

A2 = (2 +2)!/(2 +2)

= 4!/4

A2 = (1*2*3*4) /4

A2 = 6

A3 is the third term

A3 = (3 + 2)!/(3 +2)

A3 = 5!/5

A3 = 24

A4 is the fourth term

A4 = (4 + 2)!/(4 + 2)

A4 = 6!/6

A4 = 120

A5 is the fifth term

A5 = (5 + 2)!/(5 +2)

A5 = 7!/7

A5 = 720

Answer: C) 2,6,24,120,720

Thank you.

8 0
3 years ago
Solve the equation for x.
ivann1987 [24]

Answer:

x = 44

Step-by-step explanation:

sqrt(x+5) -3 =4

Add 3 to each side

sqrt(x+5) -3+3 =4+3

sqrt(x+5)  =7

Square each side

(sqrt(x+5))^2  =7^2

x+5 = 49

Subtract 5 from each side

x+5-5 = 49-5

x=44

3 0
3 years ago
Read 2 more answers
Determine whether the given value is a statistic or a parameter. A sample of seniors is selected and it is found that 65% own a
sp2606 [1]

Answer: A. Statistic because the value is a numerical measurement describing a characteristic of a sample.

Step-by-step explanation: Statistic are used to describe values obtained from a data sample which are regarded as a subset of the data belonging to an entire population. Therefore, in statistical parlance, numerical measurement obtained from such dataset are called statistic. On the other hand, if data from which a numerical derivation was made is a population which consists of the entire set of observations belonging to a particular group of interest, then the numerical values obtained are referred to as a parameter.

5 0
3 years ago
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