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Sloan [31]
2 years ago
5

Part A

Mathematics
1 answer:
labwork [276]2 years ago
5 0

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:

i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles

ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles

iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.

In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.

So that;

The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = \frac{3}{2}

  = 1.5

The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

            = 6

The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.

And,

5y = 5(1.5)

    = 7.5

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

#SPJ1

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