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2 years ago

Can anyone help???

Mathematics

1 answer:

svp [43]2 years ago

8 0

Answer:

-8x+21

Step-by-step explanation:

Use the distributive property.

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Use prime factorization to find the greatest common factor of 56 and 84

sdas [7]

Answer:

Step-by-step explanation:

Hope this helped.

6 0

2 years ago

5.47 - (-2.8) pls help me

Dominik [7]

Answer:

8.27

Step-by-step explanation:

subtracting a negative number creates a positive

two negatives = a positive

6 0

3 years ago

Read 2 more answers

Please help asap !!!!!

Natasha2012 [34]

Answer:

XY = 92 units

Step-by-step explanation:

Similar Shapes

Two shapes are similar if all their corresponding side measures are in the same proportion.

The triangles UVW and YVX are similar because their side lengths are in the proportion 1:2, given the tick marks provided in the drawing.

This means that the measure of VX is twice the measure of VW,

The measure of YV is twice the measure of UV

The measure of XY is twice the measure of UW

This last proportion gives the equation:

z + 46 = 2z

Solving for z:

z = 46

Thus, XY = z+46 = 92

XY = 92 units

6 0

3 years ago

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that 5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

 $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

Use this picture to solve for X

Zepler [3.9K]

Answer:

x=2

Step-by-step explanation:

i would set up a system of equation using the pythagorean theorem:

1^2+x^2=z^2

4^2+x^2=y^2

Add up these equations to get:

17+2x^2=y^2+z^2

But notice that

y^2+z^2=5^2

So you can substitute

17+2x^2=25

2x^2=8

x^2=4

x=2

8 0

2 years ago