Someone please help me with this question! How can I prove it?
2 answers:
For triangles to be congruent by SAS congruency criteria, one angle and the two adjacent sides to the angle should be equal to corresponding angle and it's adjacent aides of another triangle.
And we have already been given the angle and one of the side. so the third side that need to be equal in both side to pe proved congruent are :
- TS = QV
- Correct option is 1
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Answer:
The equation of the parabola is y = 6-2b+1
Step-by-step explanation:
First we write a quadratic equation of parabola as y = a+bx+c
Now it is given in the question that parabola passes through three points (-5,161),(-2,29),(6,205).
To find the equation we have to get the value of a,b & c.
Now we form three equations to find the value of a,b,c.
We put the value (-5,161) in the equation
161 = a×25+b×(-5)+c
161 = 25a-5b+c----------(1)
Now we put (-2,29) in the equation
29 = a×4+b×(-2)+c
29 = 4a-2b+c---------(2)
Again we put (6,205) in the equation
205 = a×36+6b+c------------(3)
Now we subtract equation (1) from (2)
161-29 = 25a-4a-5b-(-2b)+c-c
132 = 21a-5b+2b
132 = 21a-3b
132 = 3(7a-b)
44 = 7a-b---------(4)
Now we subtract equation (2) from (3)
205-29 = 36a-4a+6b-(-2b)+c-c
176 = 32a+6b+2b
176 = 32a+8b
176 = 8(4a+b)
22 = 4a+b------------(5)
Now we add equation (5) and (4)
44+22 = 7a+4a-b+b
66 = 11a
a = 6
Now we put the value a in equation (4)
44 = 7×6-b
44 = 42-b
44-42 = -b
2 = (-b)
b = (-2)
Now we put the value of a and b in equation number (2)
29 = 4×6-2(-2)+c
29 = 24+4+c
29 = 28+c
c = 29-28
c =1
Finally we put the value of a,b,c in the quadratic equation
y = 6+(-2)x+1
y = 6-2+1
This is the final answer.