Answer:
The answer is "$ 4450"
Step-by-step explanation:
Purchased policy price = $50,000
10th anniversary cash value = ?
The after calculation its final value is = $ 4450
For number one the second card must be positive or he would have to put it back if its negative for number 2 the card must be 3 4 5 because negative 2 plus 3 is 1 which is positive and negative 2 plus 4 and 5 would allow her to keep her cards. for the third one danny could have pulled a negaitive 1 2 3 4 and 5. oh dude i forgot to put decimals but still the same thing
For this case we must simplify the following expression:

So, if we apply distributive property to the terms within parentheses we have:

We simplify taking into account that:
- Equal signs are added and the same sign is placed.
- Different signs are subtracted and the major sign is placed.

Answer:

The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
<h3>How can the dimensions and volume of the box be calculated?</h3>
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;

Which gives;

6•x² - 106•x + 315 = 0

Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
Learn more about differentiation and integration here:
brainly.com/question/13058734
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Answer: the line is no longer linear
Step-by-step explanation: