Step-by-step explanation:
Graph it and find the rise over run. which then gives you your slope
Answer: Phillip is correct. The triangles are <u>not </u>congruent.
How do we know this? Because triangle ABC has the 15 inch side between the two angles 50 and 60 degrees. The other triangle must have the same set up (just with different letters XYZ). This isn't the case. The 15 inch side for triangle XYZ is between the 50 and 70 degree angle.
This mismatch means we cannot use the "S" in the ASA or AAS simply because we don't have a proper corresponding pair of sides. If we knew AB, BC, XZ or YZ, then we might be able to use ASA or AAS.
At this point, there isn't enough information. So that means John and Mary are incorrect, leaving Phillip to be correct by default.
Note: Phillip may be wrong and the triangles could be congruent, but again, we don't have enough info. If there was an answer choice simply saying "there isn't enough info to say either if the triangles are congruent or not", then this would be the best answer. Unfortunately, it looks like this answer is missing. So what I bolded above is the next best thing.
Assignment: 
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Answer: 
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Explanation: 
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[ Step One ] Rewrite 

[ Step Two ] Rewrite Equation

[ Step Three ] Apply Exponent Rule
Note: 

[ Step Four ] Refine

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Answer:
5/4
Step-by-step explanation:
Using coordinates (10,0) and (90,100)
Slope m = (y2-y1)/(x2-x1)
m = (100 - 0)/(90 - 10) = 100/80 = 10/8 = 5/4
Answer:
570 m³
Step-by-step explanation:
The volume of water is the product of flow rate of water and the time taken. We are to get the volume of water used between 6 am and 9 am, that is for 3 hours (9 - 6).
We are given the flow rate at 6 am and the flow rate at 9 am, but this flow rate changes between 6 am and 9 am. To get the estimate of the water used, Let us assume that it flows at the same flow rate as it was at 6 am throughout, hence:

Also, let us assume that it flows at the same flow rate as it was at 9 am throughout, hence:

To get the best estimate of the total volume, let us find the average of the two values, hence:
