Answer:
0.9375
Step-by-step explanation:
Given the following :
Number of coin tosses = 7
Probability that number of heads obtained will be between 2 and 7 inclusive?
x = 2,3,4,5,6,7
Probability (P) = number of required outcomes / total possible outcomes
For a coin toss = 1 Head (H), 1 tail (T)
P(H) = 1 / 2
P(X) = C(7,x) * (1/2)^7
P(X) = C(7, x) / 0.5^-7
P(X) = [C(7,2) + C(7, 3)+ C(7,4) +C(7,5) + C(7,6) +C(7,7)] / 128
P(X) = (21 + 35 + 35 + 21 + 7 + 1) / 128
P(X) = 120 / 128
P(X) = 0.9375
The lcf of 8 and 56 is 2, the lcf of 12 and 30 is 2, the lcf of 16 and 24 is 2, and the lcf of 9 and 15 is 3.
Answer:
B. -255
Step-by-step explanation:
This picture is from the user of: DBlaze.
Since the first term is -5 and the difference is 6 so a2=1,a3=7,a4=13,a5=19. Hope that helped. if you have any questions regarding how I got the values, feel free to ask. :')
