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2 years ago

Does (1, 5) make the equation y = 3x true?

Mathematics

2 answers:

prisoha [69]2 years ago

6 0

Answer:…

Step-by-step explanation:

Vinil7 [7]2 years ago

5 0

Answer:

No, it does not make it true.

Step-by-step explanation:

The parenthesis is written in (x, y) fashion so x = 1 and y = 5. Plug the numbers in the equation. 5 = 3 (1) is NOT true. 3 x 1 = 3 which does not equal 5.

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Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at $(0,1)$ .

The graph has an x-intercept at $(-7,0)$ .

Step-by-step explanation:

Given: The graph is $y=\sqrt[3]{x-1}+2$

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of $(-\infty, \infty)$ .

To find the y-intercept: To find the y-intercept, substitute $x=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}$

Thus, the y-intercept is $(0,1)$

To find the x-intercept: To find the x-intercept, substitute $y=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}$

Thus, the x-intercept is $(-7,0)$

8 0

3 years ago

Read 2 more answers

Solve pls <br> 2x - 5 = 7

storchak [24]

Answer:

Step-by-step explanation:

$2x - 5 = 7 \\ 2x = 12 \\ x = 6$

4 0

3 years ago

Read 2 more answers

Use compatible numbers to find two estimates 18÷1322

marysya [2.9K]

0.0135135135135135135135135 etc

8 0

4 years ago

4x+6=4+(2x+1) is the answer 6=6

seropon [69]

Answer:

Step-by-step explanation:

4x+6=4+(2x+1)

Opening bracket

4x + 6 = 4 + 2x + 1

Collecting like terms

4x - 2x = 4 + 1 - 6

2x = -1

x = -1/2

4 0

3 years ago

Read 2 more answers

Question 10

Bond [772]

Answer:

( x - 2)^2 + ( y - 3)^2 = 34

Step-by-step explanation:

The equation of the circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( a, b) - the center of the circle

( x, y) - any point on the circle

r^2 - radius of the circle

( -3 , 6) - point - ( x, y)

x = -3

y = 6

( 2 , 3) - center-( a, b)

a = 2

b = 3

Step 1: substitute the center into the equation

( x - 2)^2 + ( y - 3)^2 = r^2

Step 2: sub the point into the equation

( x - 2)^2 + ( y - 3)^2 = r^2

( -3 - 2)^2 + ( 6 - 3)^2 = r^2

( -5)^2 + 3^2 = r^2

25 + 9 = r^2

34 = r^2

Step 3: sub the radius into the equation

( x - 2)^2 + ( y - 3)^2 = r^2

( x - 2)^2 + ( y - 3)^2 = 34

Therefore, the equation of the circle is

( x - 2)^2 + ( y - 3)^2 = 34

3 0

4 years ago