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Nataliya [291]
3 years ago
15

Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

Mathematics
2 answers:
SOVA2 [1]3 years ago
8 0

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

timama [110]3 years ago
4 0

Answer:

A. D. and E.

(this is for edg btw)

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Consider a sequence given by the formula f(n)=3n-1 starting with n=1. Generate the first 5 terms of the sequence
Rufina [12.5K]

Answer:

The first 5 terms are 2, 5, 8, 11, 14.

Step-by-step explanation:

  1. You use the formula to find out each term.
  2. f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
  3. Now to find each term:
  • n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
  • n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
  • n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
  • n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
  • n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14

So the first 5 terms are 2,5,8,11,14

5 0
3 years ago
3.1 Find the equation of the line passing through (4, 5) and parallel to the line 3x – 2y = 4.
valentinak56 [21]

                   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

            <em>Find the equation of the line passing through (4, 5) and parallel to </em>

<em>                 3x-2y=4.</em>

<em />

<em>  </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

\rightarrow First, add 2y on both sides:-

                            \Large\textsf{3x+2y=4}

\rightarrow Now, subtract 3x on both sides:-

                  \Large\textsf{2y=-3x+4}

\rightarrow Divide by 2 on both sides

    \Large\text{$y=-\displaystyle\frac{3}{2}x +2$}

\rule{300}{3}

Now, let's find the equation of the line that's parallel to the given line.

Remember, if lines are parallel to each other, then their slope's the same.

So the slope of the line that's parallel to the line whose equation we just found, is

\Large\text{$-\displaystyle\frac{3}{2}$}

Now let's write the equation in point-slope form:-

\hookrightarrow\sf{y-y_1=m(x-x_1)}

Replace numbers with letters, as follows:-

\sf{y-5=-\displaystyle\frac{3}{2} (x-4)}

The equation above is the equation in point-slope form.

Incase you need it converted to slope intercept form, refer to the steps below ~

Multiply -3/2 times x and -4:-

\hookrightarrow\sf{y-5=-\displaystyle\frac{3}{2} x-6}

Now, Add 5 on both sides:-

\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}

\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

4 0
2 years ago
−7=y7 please help me out
Yuri [45]

Answer:

Step-by-step explanation:

y=-1

7 0
2 years ago
Read 2 more answers
Use doubles minus one to slove 8+7
bearhunter [10]
I got 30 as an answer
8 0
3 years ago
Solve -8/5 x - 6 = -54
Musya8 [376]
The equation is false so no solution.

Simplify 8/5 * -6 to -48/5

Move the negative sign to the left

Simplify brackets

Since 48/5 = -54 its false so no answer
4 0
3 years ago
Read 2 more answers
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