Answer is 86.47 cm hope helped
To solve this question, you just need to count all the probability of the options.
The probability that a pitch not over the plate is a strike is zero. So, P(A | D) = 0.
True. It is 0/0+20= 0
The probability that a pitch not over the plate is a ball is 1. So, P(B | D) = 1.
True, it is 20/20+0= 1
The probability that a pitch over the plate is a strike is 10:15. So, ...
Incomplete but it sounds to be true. It should be 10/10+5= 10/15 = 2/3
The probability that a pitch over the plate is a ball is 5:10. So, P(B | C) = 0.5.
We can say that exchanging one couple's ticket for an individual's ticket would increase the money in the cash box from 200 to 202 and it would result in an even number of couples tickets sold.
<u>Step-by-step explanation:</u>
Let the number of tickets sold to the individuals = s
Let the number of tickets sold to the couples = c
According to the question,
s + c = 46 ( Equation 1)
Since each individual's ticket is $6, the total amount of money made by selling tickets to individuals is 6s.
Similarly, since each ticket sold to couples is $8, the total amount of money made by selling tickets to couples is 8c.
So,
6 s + 8 c = 200 ( Equation 2)
On solving both the equations, we get
c = 38 and s = 8
Therefore, 8 tickets were sold to individuals and 38 tickets were sold to the couples.
Answer:
<h2>2 x 2</h2>
Step-by-step explanation:
Dimensions: m x n
m = number of rows
n = number of columns
When multiplying two matrices:
m x n * n x k = m x k
MATIX 1:
m = number of rows
n = number of columns
MATRIX 2:
n = number of rows
k = number of columns
RESULTING MATIX:
m = number of rows
k = number of columns
2 x 3 * 3 x 2 = 2 x 2
