Answer:
4, it's obvious think of it as a quarter.
Step-by-step explanation:
1 = 25%
2 = 50%
3 = 75%
4 = 100%
Answer:
16. Angle C is approximately 13.0 degrees.
17. The length of segment BC is approximately 45.0.
18. Angle B is approximately 26.0 degrees.
15. The length of segment DF "e" is approximately 12.9.
Step-by-step explanation:
<h3>16</h3>
By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.
For triangle ABC:
,- The opposite side of angle A
, - The angle C is to be found, and
- The length of the side opposite to angle C
.
.
.
.
Note that the inverse sine function here
is also known as arcsin.
<h3>17</h3>
By the law of cosine,
,
where
,
, and
are the lengths of sides of triangle ABC, and
is the cosine of angle C.
For triangle ABC:
,
, - The length of
(segment BC) is to be found, and - The cosine of angle A is
.
Therefore, replace C in the equation with A, and the law of cosine will become:
.
.
<h3>18</h3>
For triangle ABC:
,
,
, and- Angle B is to be found.
Start by finding the cosine of angle B. Apply the law of cosine.
.
.
.
<h3>15</h3>
For triangle DEF:
- The length of segment DF is to be found,
- The length of segment EF is 9,
- The sine of angle E is
, and - The sine of angle D is
.
Apply the law of sine:

.
Answer:
non mutually exclusive event
Step-by-step explanation:
im not sure on this tho
A. all real numbers for both
Explanation:
Domain is the x-values. Since the graph goes forever horizontally, any x-value is on the graph.
Range is the same but with y-values. If the graph went on further than what the picture shows, then it also would show that every y value is on the graph
hope this helps
Answer:
-4
Step-by-step explanation:
Find the gradient of the line segment between the points (0,2) and (-2,10).
Given data
x1= 0
x2= -2
y1= 2
y2=10
The expression for the gradient is given as
M= y2-y1/x2-x1
substitute
M= 10-2/-2-0
M= 8/-2
m= -4
Hence the gradient is -4