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lara31 [8.8K]
3 years ago
6

Look at the figure shown below:

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

Using SAS postulate, prove that triangles PQS and PRS are congruent.

Step-by-step explanation:

Just took the quiz.

boyakko [2]3 years ago
6 0

These are the steps, with their explanations and conclusions:


1) Draw two triangles: ΔRSP and ΔQSP.


2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).


3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.


4) The segment SP is common to both ΔRSP and Δ QSP.


5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.


Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q


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The diagram shows two nested triangles that share a vertex.Find a center and a scale factor for a dilation that would move the l
nasty-shy [4]

Transformation that changes the size of a shape is referred to as dilation.

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<u>The center of dilation</u>

From the diagram (see attachment), the triangles share a common vertex at (-1,1)

This means that, the center of dilation is (-1,1)

<u>The scale factor of dilation</u>

To do this, we divide the side length of the small triangle with the corresponding side of the large triangle.

From the attached image:

\mathbf{Base\ of\ small\ triangle = 1}

\mathbf{Base\ of\ large\ triangle = 5}

So, the scale factor (k) from large to small is:

\mathbf{k = \frac{Base\ of\ small\ triangle}{Base\ of\ large\ triangle} }

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brainly.com/question/13176891

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What is the area of the right triangle with sides 10,26 and 24
solniwko [45]
Answer:

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Area = 1/2 bh

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In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

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and we know using sets

n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )

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3 years ago
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