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ira [324]
3 years ago
10

Please Help ;-;

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-8, -8) and (-7, 9). Substitute to the formula of a slope:

m=\dfrac{9-(-8)}{-7-(-8)}=\dfrac{17}{1}=17

Put the coordinates of the point (-7, 9) and the value of slope to the point-slope formula:

y-9=17(x-(-7))\\\\\boxed{y-9=17(x+7)}

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a swimming pool is 8ft longer than it is wide. the pool is surrounded by a walkway of width 4ft. the combined area of the pool a
vladimir1956 [14]
8*4 = 32 then 32 / 1280 =  40 as the dimensions.
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3 years ago
A recipes calls for 1/4 cups of flour. Carter only has a measuring cup that holds 1/8 cup. how can carter measure the flour he n
deff fn [24]
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3 years ago
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1. Which of the following shows the value of (4.3 x 10-7)(1.5 x 10-3) in scientific notation? a. 6.45 x 10-10 b. 64.5 x 10-9 C.
elena55 [62]

The product of the expression in scientific notation is expressed as 6.45 * 10^-9

<h3>Scientific notations</h3>

The standard scientific notation is expressed as:

A * 10^n

A is any value between 1 and 10

n is any integer

Given the product

(4.3 x 10-7)(1.5 x 10-3)

= (4.3 * 1.5)(10^-7 * 10^-3)
= 64.5 * 10^-10
= 6.45 * 10^-9

Hence the product of the expression in scientific notation is expressed as 6.45 * 10^-9

Learn more on scientific notation here: brainly.com/question/5756316

#SPJ1

5 0
2 years ago
Jillian receives a $30 gift card to use at a movie theater. She spends $11 on her movie ticket and she wants to spend the remain
abruzzese [7]
2, 3, and 5.
Hope this could help.
rrriok, the home of...idk
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4 years ago
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C xy2 ds, c is the right half of the circle x2 y2 = 4 oriented counterclockwise
Kryger [21]
Parameterize the contour by

C:\mathbf r(t)=(2\cos t,2\sin t)\implies \dfrac{\mathrm d\mathbf r}{\mathrm dt}=(-2\sin t,2\cos t)
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\displaystyle\int_C xy^2\,\mathrm dS=2\int_{-\pi/2}^{\pi/2}(2\cos t)(2\sin t)^2\,\mathrm dt
=\displaystyle16\int_{-\pi/2}^{\pi/2}\cos t\sin^2t\,\mathrm dt=\dfrac{32}3
6 0
4 years ago
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