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Vedmedyk [2.9K]
2 years ago
6

A 4"x6" photo is digitized using 10,000 pixels. An 11"x7" photo is digitized using 30,000 pixels. Which image will have the bett

er resolution?
the 11"x7" photo

the 4"x"6 photo

the photos will have the same resolution
Computers and Technology
1 answer:
Alenkinab [10]2 years ago
5 0

An image which will have the better resolution is: A. the 11"x7" photo.

<h3>What is a camera lens?</h3>

A camera lens can be defined as a transparent optical instrument that is used in conjunction with a digital camera, so as to refract rays of light coming into the lens.

<h3>What is a resolution?</h3>

A resolution can be defined as the number of pixels that are contained in an image (picture or photo) or on a display monitor of a computer system such a laptop.

In this scenario, we can infer an logically deduce that an image which will have the better resolution is the 11"x7" photo because it has a higher number of pixel (30,000 pixels) than the 4"x"6 photo.

Read more on resolution here: brainly.com/question/14294025

#SPJ1

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[20 pts] Write the function rectangle(perimeter, area), which takes two positive integers, perimeter and area. It returns an int
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Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.

Answer:

import math

def rectangle(perimeter, area):

   l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4

   l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4

   l2_1 = area/l1_1

   l2_2 = area/l1_2

   print(l1_1,l2_1)

   print(l1_2,l2_2)

   if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:

       return(int(max(l1_1,l2_1)))

   elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:

       return(int(max(l1_2,l2_2)))

   else:

       return(None)

Explanation:

  • We import math to make basic operations
  • We define the rectangle function that receives perimeter and area
  • We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
  • We calculate the second root of the quadratic equation for the same side (l1_2)
  • We calculate the second side of the rectangle using the first root on w = a/h
  • We calculate the second side of the rectangle using the second root on w= a/h
  • We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
  • If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
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