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german
2 years ago
10

Diane, a developer, needs to program a logic component that will allow the user to enter a series of values

Computers and Technology
1 answer:
oee [108]2 years ago
3 0
<h2>The Examples Of Users:</h2>
  • Form
  • Table
  • Query
<h2>The Answers Are:</h2>
  • Formatted summary of information from a database

  • User-friendly interface for adding to or retrieving information from a database

  • Stores raw data in a relational database

  • Retrieves specific information from a database. Can also be used to update, edit, and remove data
<h2>Hope it helps*^-^*All Correct!?</h2>
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One of the biggest risks involved in using e-mail is
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The best answer to the question that is being presented above would be letter d. One of the biggest risks involved in using electronic mail or e-mail is the amount of junk mail you get from unsolicited, spamming, and phishing e-mail addresses.
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3 years ago
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Write a c program to count the total number of commented characters and words in a c file taking both types of c file comments (
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#include<stdio.h>

#include<stdlib.h>

int comment1(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\n')

       {

           return count;

       }

       count++;

   }

   return count;

}

int comment2(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='*')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               return count;

           }

           count++;

       }

       count++;

   }

   return 0;

}

int main()

{

   printf("Enter the file name:");

   char s[1000],ch,ch1;

   scanf("%s",s);

   FILE*fp;

   fp = fopen(s,"r");

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\"')

       {

           while(fscanf(fp,"%c",&ch)!=EOF)

           {

               if(ch=='\"')

               {

                   break;

               }

               if(ch=='\\')

               {

                   fscanf(fp,"%c",&ch);

               }

           }

       }

       else if(ch=='/')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               count += comment1(fp);

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   printf("%d\n",count);

   return 0;    

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The Sleeping-Barber Problem:
s2008m [1.1K]

Answer:

Explanation:

Following are the Semaphores:

Customers: Counts waiting customers;

Barbers: Number of idle barbers (0 or 1)

mutex: Used for mutual exclusion.

Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves

Shared data variable:

count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.

// shared data

semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;

int count_cust= 0;

void barber() {

while(true) { //shop is always open

wait(customers); //sleep when there are no waiting customers

wait(mutex); //mutex for accessing customers1

count_cust= count_cust-1; //customer left

signal(barbers);

signal(mutex);

cut_hair();

}

}

void customer() {

wait(mutex); //mutex for accessing count_cust

if (count_cust< n) {

count_cust= count_cust+1; //new customer

signal(customers); signal(mutex);

wait(barbers); //wait for available barbers get_haircut();

}

else { //do nothing (leave) when all chairs are used. signal(mutex);

}

}

cut_hair(){ waiting(cutting);

}

get_haircut(){

get hair cut for some time; signal(cutting);

}

6 0
3 years ago
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