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EleoNora [17]
2 years ago
12

As x → − ∞ , f ( x ) = − 3 . As x → ∞ , f ( x ) = − 3

Mathematics
1 answer:
Ludmilka [50]2 years ago
4 0

Answer:

hi

Step-by-step explanation:

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Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1.
Yuki888 [10]

Answer:

true for all x

Step-by-step explanation:

3x - 4 ≤ 2

Add 4 to each side

3x - 4+4 ≤ 2+4

3x<6

Divide by 3

3x/3 <6/3

x<2

or

2x + 11 ≥ -1

Subtract 11 from each side

2x + 11-11 ≥ -1-11

2x≥ -12

Divide by 2

2x/2 ≥ -12/2

x  ≥ -6

x<2  or x  ≥ -6

true for all x

6 0
2 years ago
Learning math. The Core Plus Mathematics Project (CPMP) is an innovative approach to teaching mathematics that engages students
jek_recluse [69]

Answer:

D is the answer

Step-by-step explanation:

5 0
2 years ago
Write an equation for a line parallel to y=2x -1 that passes through (-1, 6).
exis [7]

I think it’s Y = 2x + 8

4 0
3 years ago
InWrite the equation of the line that passes through (7, - 4) and (- 1, 2) slope- intercept form.
blondinia [14]

Answer:

General Equation of a Line

General Equation \\(y - y_{1} )= m (x-x_{1}) \\Slope=m= \frac{x_{2}-x_{1} }{y_{2}-y_{1} } \\\\Given:\\p_{1}=(7,-4)\\p_{2}=(-1,2)\\Solution:\\m=(\frac{-1-7}{2-(-4)}) =\frac{-8}{6}\\y-(-4) = (\frac{-8}{6} )(x-7)\\y+4=\frac{-8x}{6} + 56\\y=\frac{-8x}{6} + 52 \\\\The\\  equation \\ is \\ y=\frac{-8x}{6} + 52

Step-by-step explanation:

Find the slope first and then place the values on the general formula. The final step is to solve for y

5 0
3 years ago
Describe the relationship between the area of a circle and its circumstances
valentina_108 [34]

Answer:

A = \frac{r}{2}C

Step-by-step explanation:

Given

Shape: Circle

Required

The area and the circumference (relationship)

This implies that, we write an expression that relates the area and the circumference.

Circumference is calculated as:

C = 2\pi r

Area is calculated as:

A = \pi r^2

The area can be rewritten as:

A = \frac{2\pi r^2}{2}

Further rewrite as:

A = \frac{r}{2}*2\pi r

Recall that:C = 2\pi r

So, the expression becomes

A = \frac{r}{2}*C

A = \frac{r}{2}C

6 0
3 years ago
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