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2 years ago

I would only like help with these two questions can someone please help me? :)

Mathematics

1 answer:

omeli [17]2 years ago

3 0

x is the numbers across the bottom and Y is the numbers on the sides

coordinates are written (x,y)

so for 1. A is at (1,3) B is (0,5) you can find the rest

for number 2

(2,1) is D, (3,1) is F you can find the rest.

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Y = x² + 7x - 5 Can be written in the form y = ( x + a )² + b. Find the value of a and the value of b.

Mamont248 [21]

Answer:

$a=\dfrac{7}{2} \\\\b=\dfrac{49}{4} \\$

Step-by-step explanation:

$y=x^2+7x-5\\\\=x^2+2*\dfrac{7}{2}*x +\dfrac{49}{4} -\dfrac{49}{4} -\dfrac{20}{4} \\\\=(x+\dfrac{7}{2} )^2+\dfrac{69}{4} \\\\a=\dfrac{7}{2} \\\\b=\dfrac{49}{4} \\$

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2 years ago

Camila owns a car worth $5,900 and owes $2,800 on the car loan. She has $1,600 in her bank account and $5,210 in a savings accou

ohaa [14]

Answer:

$Net\ Worth=11310$

Step-by-step explanation:

From the question we are told that:

Car worth $C=5900\$$

Car Loan $L=2800\$$

Bank account $B= 1600\%$

Savings account $S=5210\&$

Credit card $CC=1400\%$

Generally Net worth is the value of the assets a person or corporation owns, minus the liabilities they owe.

Therefore

$Net\ Worth=Asset-Liability\\\\Net\ Worth=Car worth+Bank account+Savings account +Credit card-Car Loan\\\\Net\ Worth=5900+1600+5210+1400-2800$

$Net\ Worth=11310$

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2 years ago

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The photoreceptors called __ respond best to dim light, and those called __ enable color vision

Makovka662 [10]

retina, rods and cones

6 0

3 years ago

Share ur negativity…

Dima020 [189]

Answer:

I'm almost 30,000 dollars in debt

Step-by-step explanation:

It makes me cry

7 0

2 years ago

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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r

erastova [34]

Answer:

The probability is $\frac{56!}{64!}$

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, $64 \choose 8 .$

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function $f : A \rightarrow A ,$ with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

$\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}$

7 0

2 years ago