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2 years ago

Given the functions f and g, explain why you cannot find f⋅g.

Mathematics

2 answers:

Delvig [45]2 years ago

6 0

We can't write the product because there is no common input in the tables of g(x) and f(x).

<h3>Why you cannot find the product between the two functions?</h3>

If two functions f(x) and g(x) are known, then the product between the functions is straightforward.

g(x)*f(x)

Now, if we only have some coordinate pairs belonging to the function, we only can write the product if we have two coordinate pairs with the same input.

For example, if we know that (a, b) belongs to f(x) and (a, c) belongs to g(x), then we can get the product evaluated in a as:

(g*f)(a) = f(a)*g(a) = b*c

Particularly, in this case, we can see that there is no common input in the two tables, then we can't write the product of the two functions.

If you want to learn more about product between functions:

brainly.com/question/4854699

#SPJ1

zhenek [66]2 years ago

4 0

Answer:

cuz

stuff

Step-by-step explanation:

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3 years ago

What is the exact value of the expression the square root of 486. − the square root of 24. + the square root of 6.? Simplify if

kenny6666 [7]

Sqrt(486) - sqrt(24) + sqrt(6)

find the factors of 486 that we can remove from under the square root sign
2 * 243
2 * 3 * 81
2 * 3 * 9 * 9 (we have 2 nines, we can move a 9 outside the sqrt sign)
sqrt(486) = 9 sqrt(6)

Repeating for sqrt(24)
2 * 12
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Finally, add all 3 terms together

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3 years ago

if a coin is tossed 4 times, the odds of it coming up either heads every time or tails every time are 1:7.What is the probabilit

ivanzaharov [21]

Answer:

$1$

Explanation:

From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses

What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin

For four throws, it means all four are heads or all four are tails

If all four are heads, we have the probability of this happening as:

$\text{ (}\frac{1}{8})^{}$

if all four are tails, we have the probability as:

$\frac{7}{8}$

Now, the probability of either heads or all tails after 4 tosses will be:

$\text{ }\frac{1}{8}\text{ + }\frac{7}{8}\text{ = 1}$

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1 year ago