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Talja [164]
3 years ago
14

In order to estimate the proportion of all likely voters who will likely vote for the incumbent in the upcoming city’s mayoral r

ace, a random sample of 267 likely voters is taken, finding that 65% state they will likely vote for the incumbent.​ The polling agency wishes to test whether there is evidence that more than 50% of likely voters will likely vote for the incumbent. Evaluate the strength of evidence for this hypothesis.​
Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0

Answer:

Yes, there is evidence that more than 50% of likely voters will likely vote for the incumbent.

Step-by-step explanation:

We are given that in order to estimate the proportion of all likely voters who will likely vote for the incumbent in the upcoming city’s mayoral race, a random sample of 267 likely voters is taken, finding that 65% state they will likely vote for the incumbent.​

The polling agency wishes to test whether there is evidence that more than 50% of likely voters will likely vote for the incumbent.

<em>Let p = proportion of  voters who will likely vote for the incumbent</em>

SO, <u>Null Hypothesis</u>, H_0 : p \leq 50%   {means that less than or equal to 50% of likely voters will likely vote for the incumbent}

<u>Alternate Hypothesis</u>, H_A : p > 50%   {means that more than 50% of likely voters will likely vote for the incumbent}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where,  \hat p = sample proportion of voters who will likely vote for the incumbent in a sample of 267 voters = 65% or 0.65

            n = sample of voters = 267

So, <em><u>test statistics</u></em>  =   \frac{0.65-0.50}{{\sqrt{\frac{0.65(1-0.65)}{267} } } } }

                               =  5.139

<em>Since in the question we are not given the level of significance so we assume it to be 5%. Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the more than 50% of likely voters will likely vote for the incumbent. The strength of the evidence is 95%.

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Step-by-step explanation:

For this case we have the following info given:

p = 0.26 represent the proportion of the company's orders come from first-time customers

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And we want to find the following probability:

p(\hat p >0.4)

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And for this case the distribution for the sample proportion is given by:

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And we can use the z score formula given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

And if we find the parameters we got:

\mu_p = 0.26

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And we can find the z score for the value of 0.4 and we got:

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And we can find this probability:

P(z>4.0119) = 1-P(z

And if we use the normal standard table or excel we got:

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