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Fiesta28 [93]
4 years ago
11

Write the greatest common factor for 12 & 32

Mathematics
2 answers:
ANTONII [103]4 years ago
3 0
<span>GCF (12,32) = 4
4 is your answer</span>
jok3333 [9.3K]4 years ago
3 0
4. You write down the factors of 12:
1x12
2x6
3x4
Then you write the one for 32:
1x32
2x16
4x8

As you can see, 1,2 and4 appear for both of the factors. 4 is the greatest of all of them. I hope this helps!
You might be interested in
I'm confuse with these questions
alexdok [17]

8 a) y=x² stretched vertically by 8

That means (0,0) stays (0,0),  and (1,1) becomes (1,8) and (-1,1) becomes (-1,8)

Answer: y = 8x²

8 b) y=x² compressed vertically by 1/5

Answer: y = (1/5) x²

9.

y = ax² + k through (-1,3) and (3,-13)

That means

3 = a (-1)² + k

-13 = a (3²) + k

Subtracting,

16 = a - 9a = -8a

a = -2

3 = -2 + k

k = 5

y = -2x² + 5

Check:

-2(-1)^2 + 5 = 3, good

-2(3)^2+5 = -18 + 5 = -13, good

Answer: a = -2, k = 5


3 0
4 years ago
-3(x+8)-12=62-24 solve
Juli2301 [7.4K]

Answer:

First we chose one side to solve.

I am doing the one on the left first.

so -3x+-24-12

-3x-12

Now we do the other side

62-24 is

38 therefore

-3x-12=38

4 0
3 years ago
Full Question On Attachment Below
allsm [11]

Answer:

115

Step-by-step explanation:

7 0
3 years ago
Do not use your calculator for Parts 1 through 4.
Hunter-Best [27]
You have to understand how piecewise functions first
I hope you do because I won't be explaining it here



1.
if it is continiuous at x=1 then the part of the function that approaches 1 from the left is the same value
so we have f(x)=3-x for x<1, so evaluate it for x=1,
we would get 3-1=2
so
if a=2 and b=3

f(x)=2x²+3x
for x=1, we get 2+3=5

it approaches 2 from the left but equals 5
2≠5
so it is not continuous because it doesn't approach the same value at x=1




2.
alright
so we established that it should approach 2 because we had the f(x)=3-x
so
f(1)=2=ax²+bx
2=a+b
the relationship is 2=a+b



3.
same as before, but use the other function, the one that is defined at x≥2
5x-10, 5(2)-10, 10-10, 0
it approaches 0
so
we must find one such that f(x)=0 for x=2 with the ax²+bx
0=a(2)²+b(2)
0=4a+2b
if we minus 2b both sides
-2b=4a
divide by 2
-b=2a
add b both sides
0=2a+b



4.
2=a+b
0=2a+b

2=a+b
minus b both sides
2-b=a
subsitute
0=2a+b
0=2(2-b)+b
0=4-2b+b
0=4-b
b=4

sub back
2-b=a
2-4=a
-2=a

a=-2
b=4


5.
graph f(x)=-2x²+4x from x=1 to x=2 and put a closed dot at (1,2) and an open dot at (2,0)
4 0
3 years ago
Tickets at a particular movie theater have different rates for adults and children. On Friday, the theater sold 4 adult tickets
Thepotemich [5.8K]

Answer: The price for the adult tickets is $12 and the price for the child ticket is $5.

Step-by-step explanation:

Let the price for the adult ticket be x

Let the price for the child ticket be y

According to question, On Friday ,

4x+7y=83

and on next day,

5x+6y=90

Now, we will use "Substitution Method" to solve the system of equations :

5x+6y=90\\\\5x=90-6y\\\\x=\frac{90-6y}{5}

so, we will put the value of x in the first equation i.e.

4x+7y=83\\\\4(\frac{90-6y}{5})+7y=83\\\\360-24y+35y=83\times 5\\\\35y-24y=415-360\\\\11y=55\\\\y=\frac{55}{11}\\\\y=5

Now, put the value of y in the equation that is given by

x=\frac{90-6y}{5}\\\\x=\frac{90-6\times 5}{5}\\\\x=\frac{90-30}{5}\\\\x=\frac{60}{5}\\\\x=\$12

Hence, the price for the adult tickets is $12 and the price for the child ticket is $5.


4 0
3 years ago
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