4 1/6 as a decimal : D

the side of the clip board appears to be a right triangle . the leg length are 2 millimeters and 2.1 millimeters and the hypoten

givi [52]

It is because u can only do pathagreom therom on right triangles.

2*2 + 2.1*2.1

4+4.41=8.41

square root of 8.41 is 2.9 so that confrms the therom which isaversa confirms it is a right triangle.

5 0

3 years ago

People in an apartment are being asked about the new maintenance policies. Only women are surveyed. a Random b Convenience c Clu

MissTica

It would be D. Stratified due to the fact that it couldn't possibly be any of the others. It isn't random because it is only women, Cluster isn't correct either, a cluster would mean "random" people which is the same as different people in a small group. It isn't Convenience due to the fact that "Convenience wouldn't even make sense in this situation. Lastly, Systematic and stratified are really close but one would still be more logical than the other.

3 0

3 years ago

the function g(t) = 2t represents the number of guitar lessons, g(t), you can complete in t months. how many guitar lessons can

Cloud [144]

T=months so if you have 7 months you would plug 7 in for (t)
making the equation g(7) = 2(7)

5 0

4 years ago

Find the polynomial of minimum degree, with real coefficients, zeros at x=4+4i and x=2, and y-intercept at 64

Mice21 [21]

Answer:

$\displaystyle -x^3+10x^2-48x+64$

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

$x= 4+4i\text{ and } x = 2$

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

$P(x)=a(x-p)(x-q)...$

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

$P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))$

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

$\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}$

Hence:

$P(x)=a(x-2)(x^2-8x+32)$

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

$64=a(0-2)(0^2-8(0)+32)$

Solve for a:

$-64a=64\Rightarrow a=-1$

Our factored polynomial is:

$P(x)=-(x-2)(x^2-8x+32)$

Finally, expand:

$\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}$

8 0

3 years ago

Got another one .. please help me again

zubka84 [21]

C and make sure next time make the pic look cleaer

5 0

3 years ago

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