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3 years ago

13

The rectangle shown has a perimeter of 154 cm and the given area. Its length is 5 more than five times its width. Write and solv

e a system of equations to find the dimensions of the rectangle.

2 answers:

Andreyy893 years ago

8 0

Answer:

2(L+W) = 34

L + W = 17

.

L*W = 52

.

L = 2W+5

.

2L + 2W = 34

L - 2W = 5

--------------- add

3L = 39

L = 13

qwelly [4]3 years ago

4 0

Answer: L= 65 cm

W= 12 cm

Step-by-step explanation:

Perimeter of rectangle = 2(l+w)

2(l+w) = 154

l + w = 77

From the question

l = 5+ 5w

So 5 + 5w + w = 77

5+ 6w = 77

6w = 72

w = 12 cm

l = 77-b = 77 - 12

= 65 cm

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Let's assume they meant C=40 degrees. With an angle like that they're asking for approximation; we'll oblige.

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Here we have remaining side given by the Law of Cosines.

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Collect like terms

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Solve for a

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See attachment for the graph

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