The rectangle shown has a perimeter of 154 cm and the given area. Its length is 5 more than five times its width. Write and solv
e a system of equations to find the dimensions of the rectangle.
2 answers:
Answer:
2(L+W) = 34
L + W = 17
.
L*W = 52
.
L = 2W+5
.
2L + 2W = 34
L - 2W = 5
--------------- add
3L = 39
L = 13
Answer: L= 65 cm
W= 12 cm
Step-by-step explanation:
Perimeter of rectangle = 2(l+w)
2(l+w) = 154
l + w = 77
From the question
l = 5+ 5w
So 5 + 5w + w = 77
5+ 6w = 77
6w = 72
w = 12 cm
l = 77-b = 77 - 12
= 65 cm
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