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Tanzania [10]
1 year ago
9

Riya is applying mulch to her garden. she applies it at a rate of 250 , 000 cm 3 250,000 cm 3 250, comma, 000, start text, space

, c, m, end text, cubed of mulch for every m 2 m 2 start text, space, m, end text, squared of garden space.
Mathematics
1 answer:
Tatiana [17]1 year ago
8 0

The rate in

\frac{ {m}^{3} }{ {m}^{2} }  \: is \:0.25\frac{ {m}^{3} }{ {m}^{2} }

<h3>How to find rate is riya applying mulch in m^3/m^2 ?</h3>

given that riya applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space.

we already know that 1m = 100cm.

so, each side of this cube is 100cm in length.

so,100 \times 100 \times 100 \: {cm}^{3}  \: in \:  {m}^{3}

To find what is the volume in cubic metres.

\frac{250000}{10000000}  =  \frac{1}{4}  = 0.25 \frac{ {m}^{3} }{ { m}^{2} }

so, the rate is0.25 \frac{ {m}^{3} }{ {m}^{2} }

Learn more about problems on garden, refer :

https://brainly.in/question/50618467

#SPJ4

Disclaimer : This question was given incomplete on portal.Here is complete question.

Question : Riya is applying mulch to her garden.She applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space. At what rate is riya applying mulch in m^3/m^2

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c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

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d) The 95% confidence interval for the odds ratio is given as follows;

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Where;

a = 1020, b = 252, c = 5343, d = 895

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95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

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ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

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