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matrenka [14]
3 years ago
5

Rewrite using a single positive exponent

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Step-by-step explanation:

\frac{ {7}^{4} }{7}  =  {7}^{4 - 1}  =  {7}^{3}

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7x=5y , find the slope and the y-intercept of each line whose equation is given.
nadezda [96]
Slope would be -7/5. The y intercept would be 5.
4 0
3 years ago
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In the figure above line m is parallel to line n.
enot [183]

<u>Given</u>:

Line m is parallel to line n.

The measure of ∠1 is (4x + 15)°

The measure of ∠2 is (9x + 35)°

We need to determine the measure of ∠1

<u>Value of x:</u>

From the figure, it is obvious that ∠1 and ∠2 are linear pairs.

Thus, we have;

\angle 1+\angle 2=180^{\circ}

Substituting the measures of ∠1 and ∠2, we get;

4x+15+9x+35=180

             13x+50=180

                     13x=130

                        x=10

Thus, the value of x is 10.

<u>Measure of ∠1:</u>

The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1

Thus, we have;

\angle 1 =4(10)+15

    =40+15

\angle 1=55^{\circ}

Thus, the measure of ∠1 is 55°

7 0
3 years ago
-6x + 18 = 7- (4x + 9) help will give brainlyist
andreyandreev [35.5K]

Answer:

X = -5

Step-by-step explanation:

-6x + 18 = 7 - (4x + 9)

first we simplify the parentheses.

distribute the invisible number one created by the negative sign in front of the parentheses to get -6x + 18 = 7 - 4x - 9

then simplify further by subtracting 9 from the right side, leaving you with

-6x + 18 = -2 - 4x

next, add 2 to both sides to isolate the variable.

-6x + 20 = -4x

then, to isolate the variable further add 6x to both sides.

20 = -4x

divide both sides by -4 to isolate the variable

-5 = x

so, x = -5

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3 years ago
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Suppose there is a pile of​ quarters, dimes, and pennies with a total value of ​$1.06. ​How much of each coin can be present wit
SpyIntel [72]
Hello,

I note (a,b,c) the result of a quarters, b dimes and c pennies:


2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)



106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0






5 0
3 years ago
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