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matrenka [14]
3 years ago
5

Rewrite using a single positive exponent

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Step-by-step explanation:

\frac{ {7}^{4} }{7}  =  {7}^{4 - 1}  =  {7}^{3}

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Each of these numbers represents the weight of a student in kilograms. What is the median of this data set?
aleksandrvk [35]

Answer:

47

Step-by-step explanation:

www.alcula.com/calculators/statistics/median/

4 0
3 years ago
Given the equation: = 4, which property should be applied first?
Ghella [55]
This is = 4 therefore no property is applied
3 0
3 years ago
What's the answer to the equation of 4x^2+25<br> and show yor work please and thank you
padilas [110]
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4 0
3 years ago
The area of a mirror is 225 Square inches, it's width is
Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

<em><u>Solution:</u></em>

Given that area of mirror is 225 square inches

width = 13\frac{3}{4} \text{ inches }

Converting the above mixed fraction we get,

width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36

Thus length of mirror is 16.36 inches

<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is \frac{55}{4} = 13.75 inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

7 0
3 years ago
Show a number line 2/3 3/3
matrenka [14]
2|------|------|------|3/3 or 1 whole
1/3. 2/3
6 0
3 years ago
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