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Lynna [10]
2 years ago
15

What is 000241 in scientific notation?

Mathematics
2 answers:
aleksley [76]2 years ago
4 0

Answer:

2.14 × 10⁻⁴

Step-by-step explanation:

Scientific notation (also called "Standard form") is written in the form

a \times 10^n , where 1\leq a < 10 and n is any positive or negative whole number.

To <u>convert</u> a number into scientific notation, move the <u>decimal point</u> to the left or right until there is one digit to the left of the decimal point.

The number of times you have moved the decimal point is the power of 10 (the value of n).

  • If the decimal point has moved to the left, n is positive.
  • If the decimal point has moved to the right, n is negative.

Therefore, to convert 0.000214 to scientific notation, move the decimal point <u>4 places to the right</u> so that a is 2.41.  As the decimal point has been moved 4 places the right, we need to multiply 2.14 by 10⁻⁴.

Therefore,  0.000214 = 2.14 × 10⁻⁴.

Pani-rosa [81]2 years ago
3 0

The number 0.000241 in scientific notation is written as 2.41 × 10-4.

Scientific notation is a way of writing very big or very small numbers. various is written in clinical notation when quite a number between 1 and 10 is increased with the aid of a power of 10. as an example, 650,000,000 may be written in medical notation as 6. 5 ✕ 10^8.

The right format for clinical notation is a x 10^b where a is more than a few or decimal quantity such that the absolute fee of a is more than or equal to one and less than ten or, 1 ≤ |a| < 10. b is the electricity of 10 required in order that the medical notation is mathematically equivalent to the original wide variety.

Scientific Notation is the expression of a number n within the shape a∗10b. where a is an integer such that 1≤|a|<10. and b is an integer too. Multiplication: To multiply numbers in clinical notation, multiply the decimal numbers. Then add the exponents of the powers of 10.

Learn more about scientific notation here brainly.com/question/1767229

#SPJ9

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Answer:

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

\bar X=52.8 represent the sample mean  for the MPG of the cars

\sigma=1.6 represent the population standard deviation

n=250 sample size  of cars

\mu_o =52.6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:  

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

Replacing we have this:

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

Decision

Since is a two tailed test the p value would be:  

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

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3 years ago
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