F(x)=2x^3-9x^2+12x-3 find the intervals on which f is increasing or decreasing
1 answer:
F'(x) = 6x^2 - 18x + 12
= 6(x^2 - 3x + 2)
= 6(x - 2)(x - 1) = 0 at turning points
at turning points x = 1 and x = 2
f''(x) = 12x - 18
so when x = 1 f''(x) <0 (maximum) and when x = 2 f''(x) > 0 (minimum)
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