Answer:
Step-by-step explanation:
Since the length of time taken on the SAT for a group of students is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = length of time
u = mean time
s = standard deviation
From the information given,
u = 2.5 hours
s = 0.25 hours
We want to find the probability that the sample mean is between two hours and three hours.. It is expressed as
P(2 lesser than or equal to x lesser than or equal to 3)
For x = 2,
z = (2 - 2.5)/0.25 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.02275
For x = 3,
z = (3 - 2.5)/0.25 = 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.97725
P(2 lesser than or equal to x lesser than or equal to 3)
= 0.97725 - 0.02275 = 0.9545
Hello
1 ) 3+4sinQ=6 ( Q is theta)
4sinQ=6 -3
sinQ=3/4 conclusion : Q= Arcsin(3/4)=......calculator
2 ) (2/7)cosQ =1/4
cosQ = 7/8 conclusion : Q= Arcsin(7/8)=....calculator
Answer:
see below
Step-by-step explanation:
1a) -5(1) + 11 = 6
1b) -5(-3) + 11 = 26
1c) -5(0) + 11 = 11
1d) -5(1.2) + 11 = 5
1e) f of x equals negative 5x plus eleven
Answer:
zdsczsczscs
Step-by-step explanation:
