Identify the input and the output given the relation described:

Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?

telo118 [61]

Answer:

The correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation:

the given equation is $5y + 4 =(x+3)^{2} + \frac{1}{2}$

Therefore we can write $5y\hspace{0.1cm} = (x+3)^{2} + \frac{1}{2} - 4 \hspace{0.3cm} \Rightarrow \hspace{0.2cm} 5y = (x+3)^{2} - \frac{7}{2} \hspace{0.3cm} \Rightarrow \hspace{0.3cm} y = \frac{(x+3)^{2}}{5} - \frac{7}{10}$

To find the inverse of the above function let us replace x with y and y with x.

Therefore we get

$x = \frac{(y+3)^{2}}{5} - \frac{7}{10}$

Now we write the above equation with only y on the Left hand side and we will obtain the inverse of the given function

$y = \pm \sqrt{5 (x + \frac{7}{10} )} \hspace{0.1cm} - \hspace{0.1cm} 3 \hspace{0.1cm} \Rightarrow\hspace{0.1cm} y = \pm \sqrt{5x + \frac{7}{2} } - \hspace{0.1cm} 3 \hspace{0.1cm}$

Therefore the correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot , $y = \pm \sqrt{5x + \frac{7}{2} } - \hspace{0.1cm} 3 \hspace{0.1cm}$

8 0

3 years ago

Read 2 more answers

A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome

Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable X represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), p = 0.52

The random variable X thus follows a Binomial distribution with parameters n = 5 and p = 0.52.

(1)

Compute the probability of overbooking as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

$=P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135$

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

$=P(X$

Thus, the probability that the flight has empty seats is 0.4625.

4 0

3 years ago

Please please please please please please please help me

Illusion [34]

Answer:

B -27

Step-by-step explanation:

7(-5)+ 6(2)-4

-35 +12-4

-23-4

-27

4 0

2 years ago

Rewrite the following fractions as division problems. a. 7⁄11 b. 5⁄2 c. 9⁄10 d. 7⁄15

d1i1m1o1n [39]

To rewrite the fractions as a division problem, use the denominator to divide the numerator. The denominator is the number below while the numerator is the number above.
1. For 7/11
Proceed as follows:
How many time will you find 11 in 7? This is not possible, so you will write down zero and put a decimal point in front of it. Then add zero at the back of 7 to get 70. How many time will 11 go in 70? That will be 6 times and you will have 4 remaining. Add zero to the back of the 4 to get 40. How many time will 11 go in 40? That will be 3 times and 7 will remain. You can continue to add zero to the remainder until you get as many decimal place as you desired.
From the calculations done above the answer we have obtained is 0.63.
Therefore, 7/11 = 0.63.

2. For 5/2, the same principle is applicable.
How many times will 2 go in 5? That will be 2 times remaining 1. Add zero to that one to obtain 10. How many times will 2 go in 10.That will be 5 times remaining zero.
Therefore 5/2 = 2.50.

3. For 9/10
How many times will 10 go in 9? That is not possible, so you will write down zero and put a decimal point in front of it. Add zero to 9 to obtain 90. How many times will 10 goes in 90. That will be 9 times exactly .
Therefore, 9/10 = 0.90.

4. For 7/15
How many time will 15 go in 7? That is not possible, so you write down zero with a decimal point in front of it. Add zero to 7 to get 70. How many times will 15 go in 70? That will be 4 times remaining 10. Add zero to the remaining 10 to obtain 100. How many time will 15 go in 100? That will be will be 6 times, remaining 10.
Therefore, 7/15 = 0.46

7 0

3 years ago

Read 2 more answers

What is the mean of 94 93 92 91 91 88 82 84

Aleksandr [31]

Answer:

89.375

Step-by-step explanation:

First, add up all the numbers. Your answer should be 715. Once you get that divide by the the total amount of numbers so you added up 8 numbers, meaning you would divide by 8. 715/8=89.375

6 0

3 years ago

Read 2 more answers