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kramer
2 years ago
9

A water wheel has a radius of 4 feet and the bottom of the wheel is 1 foot from the ground. one plank is painted white and it st

arts at the top of the wheel. the wheel is rolled forward through an angle of startfraction pi over 3 endfraction radians. how high from the ground is the white plank after this motion? 3 feet 5 feet 7 feet 9 feet
Mathematics
1 answer:
Sliva [168]2 years ago
3 0

The correct option is 9 feet.

The height from the ground the white plank after the motion is 9 feet.

<h3>What is rotational motion?</h3>

Anything that spins or moves in a circular route is said to be in rotational motion. It's also referred to as angular motion and circular motion. The motion can be uniform (— in other words, the velocity v remains constant) and non-uniform, but it must be circular.

Now, according to the question;

The wheel's radius is 4 feet.

The height of a bottom of a wheel from the ground equals 1 foot.

π/3 radians is the angle where the wheel is rolled.

The following relationship describes the height of a revolving wheel.

f(t) = A·sin(B·t + C) + D

Where,

D = Mid line =  4 + 1 = 5 feet

B·t = π/3

C = 0

amplitude; A = 4

Substituting the values in the function;

f(t) = 4×sin(π/3) + 5 = 8.464 ft

f(t) = 9 (approx)

Therefore, the plank's height after the /3π/3 rotation motion = 9 ft.

To know more about the rotational motion, here

brainly.com/question/2136775

#SPJ4

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What is the simplified form of the following expression? 2√27+√12-3√3-2√12
LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

but

2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}

\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

Since √12=2√3,this implies that,

2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

Therefore,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

=(6+2-3-4)\sqrt{3}

=\sqrt{3}

The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

8 0
3 years ago
Evelyn's made a cake in the shape of a circus tent the cake consisted of a cylinder and a cone .The height of the cone is half t
Lera25 [3.4K]
The volume of the cake is 1470 in³. 
volume of a cylinder = πr² x height
(Think about how a cylinder is basically a bunch of circles stacked on top of each other. To find the volume, first you need the area of the circle (πr², then you multiply by how many circles you are stacking on top of each other (height)) 

we know the diameter of the cylinder is 12 in. and the radius is half of the diameter. 
half of 12 is 6, therefore the radius is 6 in. or r = 6 
Assuming pi is 3.14, solve for the height of the cylinder
1470 = (3.14)(6²)(height)
1470 = 3.14 x 36 x height
1470 = 113.04 x height
height ≈ 13 in

Now that we know the height of the cylinder is about 13 in., we know the height of the cone, because the problem says that the height of the cone is half the height of the cylinder. 
half of 13 is 6.5, therefore the height of the cone is 6.5 
the radius of the cone is the same as that of the cylinder, 6 in. 

volume of a cone = πr² × (height ÷ 3)

volume of the cone = (3.14)(6²)(6.5 ÷ 3)
volume of the cone = (3.14)(36)(2.16666)
volume of the cone = 244.92 in³

Now all that's left to find the volume of the whole cake is to add the volume of the cylinder to the volume of the cone. 

1470 + 244.92 = 1714.92 in³



6 0
3 years ago
HELP!!! Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square
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2 years ago
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gladu [14]
The first thing you should observe in the graph is that
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3 years ago
I GIVVVVE BRAINLILSTE
WARRIOR [948]

Answer:

≈ 26.39 inches

Step-by-step explanation:

The circumference of a circle is 2πr or πd with r meaning radius and d for diameter. Since we know the diameter already, we can substitute the value in for d:

C = π(8.4) = 8.4π ≈ 26.39

6 0
3 years ago
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